Parker EX Series, Техническое руководство

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– Pvd3665_Gb_Ex_August 2022
Example n°2 :
This times; the application needs :
- a permanent torque of 5 Nm at low speed,
- a rms torque of 5 Nm at the rms speed of 1890 rpm,
- an acceleration torque of
7.6 Nm,
- a maximal speed of 2800 rpm.
Selection of the motor:
The selected motor is the type EX620EAO .
The nominal speed is equals to 4300 rpm.
The maximal speed is equals to 4300 rpm.
The torque sensitivity is equals to 1.27 Nm/Arms.
Selection of the drive:
The drive has to provide a permanent current equals to 4 Arms to obtain 5 Nm.
In order to obtain an acceleration torque of
7.6 Nm , the current will be of about 6 Arms
This means that the drive has to provide at less 6 Arms as transient current.
Compared to the previous example n°1, it is now possible to decrease the size of drive.
→
Therefore, we can select the drive AC890SD-53 1600 B which delivers under 400 VAC:
4 Arms as permanent current and
4* 200% = 8 Arms as maximal transient current during 4 s.
The drive is set with “Servo Mode” .