Argo ACS100PH, Технические данные и руководство по обслуживанию

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Limit of elevation
difference between
the 2 units
No additional charge of compressor oil is necessary.
*
1 If total tubing length becomes 30 to 50 m, charge additional refrigerant by 40 g/m.
Models
AES71PIC-PIH
AES100PIC-PIH AES125PIC-PIH
Tubing Data
Tubing size Narrow tube mm (in.) 9.52 (3/8) 9.52 (3/8) 9.52 (3/8)
outer diameter Wide tube mm (in.)
15.88 (5/8) 15.88 (5/8) 15.88 (5/8)
Limit of tubing length (m)
50 50 50
Outdoor unit is placed
30 30 30
higher (m)
Outdoor unit is placed
15 15 15
lower (m)
Max. allowable tubing length at shipment (m)
3 – 30 3 – 30 5 – 30
Required additional refrigerant *
1
(g/m)
a) 40 b) 40 b) 40
Refrigerant charged at shipment (kg) 1.2 1.2 1.2
Table 1-2 Tubing Data for Models (Single, Twin, Triple, Double-Twin)
25 – 48 25 – 48 12 – 18
φ
15.88
φ
15.88
φ
15.88
φ
9.52
φ
9.52
φ
9.52
φ
6.35
φ
12.7
( 1, 2, 3, 4)
20 g
40 g 40 g
40 g
Wide tube
Narrow tube
Main tubing (L)
25
Double-Twin distribution tube (L1, L2)
Total type capacity of indoor units connected after
the branch
Indoor unit connection tube
Type capacity of indoor units
Amount of additional charge per 1 m
Table 1-3 List of Connection Tube Sizes
Charge with an amount of additional refrigerant calculated using the formula below, based on the values in Table 1-3
and the size and length of the liquid (narrow) tubing.
Amount of additional refrigerant charge (g)
Do not remove refrigerant from the system, even if the result of the calculation is negative. (Use with the current
refrigerant charge.)
(a) Actual length (m) of main tubing (
φ
9.52) Refrigerant charge per 1 m of actual length = 40 g/m (25 – 48 type)
(b) Total length of distribution tubing (
φ
9.52) Refrigerant charge per 1 m of actual length = 40 g/m
(c) Total length of distribution tubing (
φ
6.35) Refrigerant charge per 1 m of actual length = 20 g/m
Example
●
Sample tubing lengths
L = 35 m 1 = 5 m
L1 = 10 m 2 = 5 m
L2 = 5 m 3 = 5 m
4 = 10 m
● Find the liquid (narrow) tube size from Table 1-3.
L :
φ
9.52 (48 type)
L1 :
φ
9.52 (Total type capacity of indoor units 24)
L2 :
φ
9.52 (Total type capacity of indoor units 24)
1 – 4 :
φ
6.35
● The amount of additional on-site refrigerant charge is found by subtracting the outdoor unit
charge-less refrigerant amount from the total charge amount for all tube sizes.
φ
9.52
→
L : 35 m
×
40 g / m = 1400
φ
9.52
→
L1 + L2 : (10 + 5) m
×
40 g / m = 600
φ
6.35
→
1 – 4 : (5 + 5 + 5 + 10) m
×
20 g / m = 500
Outdoor unit charge-less refrigerant amount –1200
Total +1300
●
The amount of additional on-site refrigerant charge is 1,300 g.
Outdoor unit
Indoor unit (12 type
×
4)
L
L1
L2
4
3
2 1
Additional refrigerant amount (g) = Additional refrigerant for main tubing (g) + Additional refrigerant for distribution tubing (g)
– Outdoor unit charge-less refrigerant amount (g)
= 40X (a) + 40X (b) + 20X (c) – 1200 (25 – 48 type)
04-309 Sanyo-1_p96-127 10/27/04 2:10 PM Page 120