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Model No. AP-8209

Photoelectric Effect Apparatus

4

Introduction

The photoelectric effect is the emission of electrons from the surface of a metal when 
electromagnetic radiation (such as visible or ultraviolet light) of the right frequency shines on the 
metal. At the time of its discovery, the classical wave model for light predicted that the energy of 
the emitted electrons would increase as the intensity (brightness) of the light increased. 
Instead it was discovered that the energy of the emitted electrons was directly proportional to the 
frequency of the incident light, and that no electrons would be emitted if the light source was not 
above a certain threshold frequency. Lower energy electrons were emitted when light with 
relatively low frequency was incident on the metal, and higher energy electrons were emitted when 
light with relatively high frequency was incident on the metal.   
The AP-8209 Photoelectric Effect Apparatus consists of a mercury light source enclosure, a 
photodiode tube enclosure, a base, the photoelectric effect test instrument, miscellaneous cords and 
cables, a power supply for the mercury light source and the test instrument, and a box of apertures, 
filters, caps, and alignment screws.
The apparatus has several important features:

• The current amplifier has high sensitivity and is very stable in order to improve the accuracy of the 

measurement.

• The photoelectric tube has low levels of dark current and anode reverse current.
• The optical filters are of high quality in order to avoid an error due to interference between different 

spectral lines.

Background Information

Many people contributed to the discovery and explanation of the photoelectric effect. In 1865 
James Clerk Maxwell predicted the existence of electromagnetic waves and concluded that light 
itself was just such a wave. Experimentalists attempted to generate and detect electromagnetic 
radiation and the first clearly successful attempt was made in 1886 by Heinrich Hertz. In the midst 
of his experimentation, he discovered that the spark produced by an electromagnetic receiver was 
more vigorous if it was exposed to ultraviolet light. In 1888 Wilhelm Hallwachs demonstrated that 
a negatively charged gold leaf electroscope would discharge more rapidly than normal if a clean 
zinc disk connected to the electroscope was exposed to ultraviolet light. In 1899, J.J. Thomson 
determined that the ultraviolet light caused electrons to be emitted from the metal.
In 1902, Phillip Lenard, an assistant to Heinrich Hertz, used a high intensity carbon arc light to 
illuminate an emitter plate. Using a collector plate and a sensitive ammeter, he was able to measure 
the small current produced when the emitter plate was exposed to light. In order to measure the 
energy of the emitted electrons, Lenard charged the collector plate negatively so that the electrons 
from the emitter plate would be repelled. He found that there was a minimum “stopping” potential 
that kept all electrons from reaching the collector. He was surprised to discover that the “stopping” 
potential, 

V

, - and therefore the energy of the emitted electrons - did 

not

 depend on the intensity of 

the light. He found that the maximum energy of the emitted electrons 

did

 depend on the color, or 

frequency, of the light.

Summary of Contents for AP-8209

Page 1: ...Instruction Manual Manual No 012 10626B Photoelectric Effect Apparatus Model No AP 8209...

Page 2: ...6 Experiment 1 Measuring and Calculating Planck s Constant 9 Experiment 2 Current Voltage Constant Frequency 13 Experiment 3 Current Voltage Constant Intensity 17 Appendix A Specifications 21 Appendi...

Page 3: ...pply 6 Photoelectric Effect Apparatus Cables and Cords Power Cord for Power Supply Power Cable for Photoelectric Effect Apparatus BNC Connector Cable for Photodiode Enclosure Banana plug Patch Cords R...

Page 4: ...to interference between different spectral lines Background Information Many people contributed to the discovery and explanation of the photoelectric effect In 1865 James Clerk Maxwell predicted the e...

Page 5: ...quanta of energy called photons with the amount of energy equal to h with as the frequency In the photoelectric effect one quantum of energy is absorbed by one electron If the electron is below the su...

Page 6: ...olors have different stopping potentials See Figure 3 The slope of a plot of stopping potential versus frequency is the value of the ratio h e See Figure 1 The photoelectric effect is almost instantan...

Page 7: ...c Effect Apparatus labeled POWER SUPPLY and the port on the h e Power Supply labeled POWER OUTPUT FOR APPARATUS Screw the knurled rings on the plug ends of the cable onto the threaded section of each...

Page 8: ...may affect the measurement accuracy First the photocurrent is extremely small Second because of the cathode dark current and the anode reverse current the voltage when the photocurrent is zero is not...

Page 9: ...IBRATION knob until the current is zero 8 Press the PHOTOTUBE SIGNAL button to MEASURE 9 Reconnect the A K and down arrow GROUND cables to the back of the apparatus Measurement 1 Uncover the window of...

Page 10: ...dix B 2 Find the slope of the best fit line through the data points on the Stopping Potential V versus Frequency x 1014 Hz graph Note The slope is the ratio of h e so Planck s constant h is the produc...

Page 11: ...value of h and the accepted value 3 How can you find the value of the Work Function from the graph of Stopping Potential versus Frequency Extension Repeat the data measurement and analysis procedure...

Page 12: ...Photoelectric Effect Apparatus 12 Questions 1 How does your calculated value of h for each different aperture compare to the accepted value h0 6 626 x 10 34 J s 2 How does light intensity affect the S...

Page 13: ...the current amplifier to zero first disconnect the A K and down arrow GROUND cables from the back panel of the apparatus 6 Press the PHOTOTUBE SIGNAL button in to CALIBRATION 7 Adjust the CURRENT CALI...

Page 14: ...y is zero Record the voltage and current in Table 4 5 Increase the voltage by a small amount e g 1 V and record the new voltage and current in Table 4 Continue to increase the voltage by the same smal...

Page 15: ...nm at the three different intensities Questions 1 How do the curves of current versus voltage for the one spectral line at three different intensities compare In other words how are the curves similar...

Page 16: ...Model No AP 8209 Photoelectric Effect Apparatus 16 Notes...

Page 17: ...10 11 5 To set the current amplifier to zero first disconnect the A K and down arrow GROUND cables from the back panel of the apparatus 6 Press the PHOTOTUBE SIGNAL button in to CALIBRATION 7 Adjust t...

Page 18: ...Continue to increase the voltage by the same small increment and record the new voltage and current each time in Table 5 Stop when you reach the end of the VOLTAGE range 577 nm Wavelength 1 Cover the...

Page 19: ...s voltage for the three spectral lines at a constant intensity compare In other words how are the curves similar to each other 2 How do the curves of current versus voltage for the three spectral line...

Page 20: ...Model No AP 8209 Photoelectric Effect Apparatus 20 Notes...

Page 21: ...Experiment menu An empty Table display and the Summary list will open Double click the Graph display icon in the bottom half of the Summary list or select Add Display from the Experiment menu and sel...

Page 22: ...nter the rest of the ordered pairs of Frequency and Stopping Potential using the same pattern Remember to press RETURN after the last datum is entered As the ordered pairs are entered they will be plo...

Page 23: ...ctric Effect Apparatus manual providing the reproductions are used only for their laboratories and are not sold for profit Reproduction under any other circumstances without the written consent of PAS...

Page 24: ...current versus voltage for a single spectral line 435 8 nm with three different apertures The next table shows typical data for current versus voltage for a constant frequency and three different aper...

Page 25: ...e of h Student answers will vary 2 What do you think may account for the difference if any between your calculated value of h and the accepted value 435 8 nm 2 mm dia V V 1 1 0 0 1 0 2 0 3 0 4 0 5 0 6...

Page 26: ...es compare In other words how are the curves similar to each other The current versus voltage curves for one spectral line and three different intensities are similar in that the stopping potential 1...

Page 27: ...l waste recycle disposal service or the place where you purchased the product The European Union WEEE Waste Electronic and Electrical Equipment symbol above and on the product or on its packaging indi...

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