Installation Manual 37
ENGLISH
Refrigerant piping installation
◆
The Amount of Refrigerant
The calculation of the additional charge should take account of the length of pipe.
WARNING
Regulation for refrigerant leakage
: the amount of refrigerant leakage should satisfy the following equation for human safety.
❐
If the above equation can not be satisfied, then follow the following steps.
- Selection of air conditioning system: select one of the next
1. Installation of effective opening part
2. Reconfirmation of outdoor unit capacity and piping length
3. Reduction of the amount of refrigerant
4. Installation of 2 or more security device (alarm for gas leakage)
- Change indoor unit type
: installation position should be over 2m from the floor (wall mounted type
→
cassette type)
- Adoption of ventilation system
: choose ordinary ventilation system or building ventilation system
- Limitation in piping work
: Prepare for earthquake and thermal stress
WARNING
Refer to model information since the CF value of correction factor differs depending
on model.
Total amount of refrigerant in the system
0.3 ( kg / m
3
)
Volume of the room at which indoor unit of the least capacity is installed
Additional charge (kg)
Product charge(kg)
=
+
+
+
+
+
+
=
+
Total liquid pipe (m): Ø22.2mm
x 0.354(kg/m)
x 0.266(kg/m)
x 0.173(kg/m)
x 0.118(kg/m)
x 0.061(kg/m)
x 0.022(kg/m)
Total liquid pipe (m): Ø19.05mm
Total liquid pipe (m): Ø15.88mm
Total liquid pipe (m): Ø12.7mm
Total liquid pipe (m): Ø9.52mm
Total liquid pipe (m): Ø6.35mm
CF(kg) (Correction factor)
Total amount(kg)
If a negative result is obtained from
the calculation, no refrigerant needs
to be added.
A
A
B
B
CAUTION
B
B
B
B
B
A
B
C
X
b
a
c
d
3
4
5
2
1
e
Outdoor Unit
Indoor Unit
A : ø9.52, 40m
B : ø9.52, 20m
C : ø9.52, 20m
Ex
10HP
Additional Charge = A x 0.061 + B x 0.061 + C x 0.061
+ (a+b+c+d+e) x 0.022 + CF
= 40 x 0.061 + 20 x 0.061 + 20 x 0.061
+ (10 x 5) x 0.022 - 0 (CF)
= 5.98(kg)
a : ø6.35, 10m
b : ø6.35, 10m
c : ø6.35, 10m
d : ø6.35, 10m
e : ø6.35, 10m
