• When a Start up DC is applied to the other circuits inside the IC,
it turns the FET ON.
• When the FET is ON there will be a short between pin2 and pin3
of the IC.
• If 0.7V is applied at pin 1, the FET turns OFF. Due to the internal
timing circuit, the FET will start again after a pre-determined time.
• If we wants to turn ON the IC prior to the internally decided
time, we can apply a 2VDC to pin1.
• This means, we can turn ON the FET and turn OFF the FET at
any time we want.
