from these solar panels, it is suitable for 1KW SR-1000-G model i
Because we should connect 4 PCS solar panels to SR-G Grid Tie Inve
As we stated at Step1, we can get a result that a 1kW SR-G G
14
Example of Installation of 1KW grid tie power system
In order to explain the installing operation, we assume that there is a house that the usual
electricity consumption is about 5KWH per day, and the real irradiation time is about 5
hours.
1, Considering the total capacity of the grid tie power system that you need.
rid Tie Power System is
suitable for this house, so we will establish a 1KW gird tie power system step by step, we
also assume that we will install the system in the house where the utility grid is 230V/50Hz.
2, Choosing applicables Solar Panels.
Because the most popular solar panels are 240Wp~250Wp poly panels with 60 PCS solar
cells, so choosing this kind type panels will be more economical. The system is 1KW power
system, so we should use 4 PCS 240Wp to 250Wp solar panels.
Most of this kind type solar panels have similar specification shown below.
Module Efficiency:14.8% Pmax:245W
Vmp:29.4V Imp:8.34A
Voc:36.9V Isc:8.68A
so use 4 PCS of this type panels, we can get total power:
TPmax = 245Wp×4 = 980Wp
nverter.
Notes:
The Pmax specification of solar panel is under STC, the actual power is variational
according to the irradiation on the panel and the temperature surroundings. The real output
power can’t reach Pmax at most time in whole day.
3,Selecting Accessory for Grid Tie Power System installation.
rter, so some
connectors are necessary. Consider of the Voc, Vmp and Isc, we choose some MC4
connectors and some connectors for parallel connecting.
For the choice of DC cables, we should consider about the connecting method of solar panels,
there are two methods can be choosed.
Method 1
: Connecting the 4 panels in parallel, so the maximum DC current will be
TImp = TPmax/TVmp = 980W/29.4V = 33.3A or
TImp = Imp × 4 = 8.34A × 4 = 33.3A
According to the Table 2, AWG6 Cables should be choosed.
Method 2
：
Connecting 2 panels in serial consist as a pair, so 4 panels can be gotten 2 pairs,
TImp = TPmax/TVmp = 980W/58.8V = 16.7A or
TImp = Imp × 2 = 8.34A × 2 = 16.7A
So according to the Table 2, AWG9 cables should be choosed.
Because the DC cables will be more expensive if the diameter is big, considering about this
matter, the method that can use smaller diameter cables will be a good choice.
