Chauvin Arnoux C.A 1875, User Manual

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92
At 10 cm ∆ s
2
= x mm
Whence:
∆ s
2
= 0.218 mm
Solution 7
Question a
The IFOV of the RayCAm is 2.2 mrad.
The minimal focal length is 10 cm.
The smallest zone that can be measured corresponds to 3 IFOV.
We therefore find:
d
1
= 3 x IFOV
10 cm
Whence:
d
1
= 0.66 mm
Question b
The IFOV of the RayCAm is 2.2 mrad.
It follows that:
at 1 m ∆ s
1
= 2.2 mm
at 50 cm ∆ s
2
= x mm
Moreover d
2
= 3 x IFOV
50 cm
= 3 x ∆ s
2
Whence:
d
2
= 3.3 mm
Solution 8
Question a
To be sure of making a valid measurement, the following value must not be
exceeded:
d
Cable
= 3 x ∆ s
2
In addition, based on the IFOV of the camera:
at 1 m ∆ s
1
= 2.2 mm
at d
1
m ∆ s
2
= d
Cable
/3
It follows that:
d
1
= ∆ s
2
/ 2.2
= (d
Cable
/3) / 2.2
Whence:
d
1
= 0.30 m = 30 cm
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