036-21581-001 Rev. B (0904)
Unitary Products Group
5
FILTER PERFORMANCE
The airflow capacity data published in the “Blower Perfor-
mance” table listed above represents blower performance
WITHOUT filters. To determine the approximate blower per-
formance of the system, apply the filter drop value for the fil-
ter being used or select an appropriate value from the “Filter
Performance” table shown below.
NOTE:
The filter pressure drop values in the “Filter Perfor-
mance” table shown below are typical values for the type of
filter listed and should only be used as a guideline. Actual
pressure drop ratings for each filter type vary between filter
manufacturer.
APPLYING FILTER PRESSURE DROP TO
DETERMINE SYSTEM AIRFLOW
To determine the approximate airflow of the unit with a filter in
place, follow the steps below:
1.
Select the filter type.
2.
Select the number of return air openings or calculate the
return opening size in square inches to determine the
proper filter pressure drop.
3.
Determine the External System Static Pressure (ESP)
without the filter.
4.
Select a filter pressure drop from the table based upon
the number of return air openings or return air opening
size and add to the ESP from Step 3 to determine the
total system static.
5.
If total system static matches a ESP value in the airflow
table (i.e. 0.20, 0.60, etc,) the system airflow corre-
sponds to the intersection of the ESP column and Model/
Blower Speed row.
6.
If the total system static falls between ESP values in the
table (i.e. 0.58, 0.75, etc.), the static pressure may be
rounded to the nearest value in the table determining the
airflow using Step 5 or calculate the airflow by using the
following example.
Example:
For a 120,000 Btuh furnace with 2 return openings
and operating on high speed blower, it is found that total sys-
tem static is 0.58" w.c. To determine the system airflow, com-
plete the following steps:
1.
Obtain the airflow values at 0.50" & 0.60" ESP.
Airflow @ 0.50": 2285 CFM
Airflow @ 0.60": 2175 CFM
2.
Subtract the airflow @ 0.50" from the airflow @ 0.60" to
obtain airflow difference.
2175 - 2285 = -110 CFM
3.
Subtract the total system static from 0.50" and divide this
difference by the difference in ESP values in the table,
0.60" - 0.50", to obtain a percentage.
(0.58 - 0.50) / (0.60 - 0.50) = 0.8
4.
Multiply percentage by airflow difference to obtain airflow
reduction.
(0.8) x (-110) = -88
5.
Subract airflow reduction value to airflow @ 0.50" to
obtain actual airflow @ 0.58" ESP.
2288 - 88 = 2197
FILTER PERFORMANCE - PRESSURE DROP INCHES W.C. AND (KPA)
Airflow Range
Minimum Opening
Size
Filter Type
Disposable
WASHABLE FIBER*
Pleated
1 Opening
2 Openings
1 Opening
2 Opening
1 Opening
2 Opening
1 Opening
2 Opening
Sq. in.
Sq. in.
In w.c.
Pa
In w.c.
Pa
In w.c.
Pa
In w.c.
Pa
In w.c.
Pa
In w.c.
Pa
0 - 750
230
0.01
2.5
0.01
2.5
0.15
37
751 - 1000
330
0.04
10
0.03
7.5
0.20
50
1001 - 1250
330
0.08
20
0.07
17
0.20
50
1251 - 1500
330
0.08
20
0.07
17
0.25
62
1501 - 1750
380
658
0.14
35
0.08
20
0.13
32
0.06
15
0.30
75
0.17
42
1751 - 2000
380
658
0.17
42
0.09
22
0.15
37
0.07
17
0.30
75
0.17
42
2001 & Above
463
658
0.17
42
0.09
22
0.15
37
0.07
17
0.30
75
0.17
42
