If we require a volume of 2.5ft
3
then we multiply this by 1728 2.5 x 1728= 4320 cubic inches
We now take 2 known enclosure dimensions that we will use E.G. height and width and divide this figure by them which will give
us the depth, for example our height is 15”, our width is 20”
So our depth is 14.4” for this enclosure
Note : this formula is for the INTERNAL dimensions, please add the thickness of the material used to construct the enclosure to
the formula to give you the outside dimensions.
So assuming we are using 1 inch material we need to add 2 thicknesses to each internal dimension to allow for material top and
bottom so the external dimensions for this enclosure would be 17 x 22 x 16.4 inches
T/S Parameters
SLICK s10
SLICK s12
Revc
3.6 Ohm
3.6 Ohm
Fo
46.476 Hz
34.5 Hz
Sd
34.600 sqM
53 sqM
BL
8.33 T
7.309 T
Qms 2.209
3.232
Qes 0.828
0.87
Qts
0.52
0.58
No
0.307%
0.40%
SPLo
88.2 dB
90.1 dB
Vas
30.901 ltr
88.095 ltr
Cms
181.773 u M/N
220.897 u M/N
Mms
64.514 g
72.815 g
Mmd
60.813 m KG
65.8 m KG
SLICK s15
3.6 Ohm
29.057 Hz
85.00 M
12.513 T
2.882
0.681
0.551
0.70 %
92 dB
166.659 m M
185.862 u M/N
162.289 g
148.040 Kg
Содержание SLICK s10
Страница 8: ...NOTES ...