(F
) U
se
Fac
tor
(T) Time (Hours)
Note. 5 seconds more are needed to assure the complete opening and closing of the door.
There are heavy use times during the day where vehicle transit is higher. Calculations should be carried out during this
period of time.
E.G.
What is the maximum working time for a door that has a pause of 30 seconds and a time between cycles of 40
seconds?
Ta+Tc
%F= x100
Ta+Tc+Tp+Ti
28+33
%F= x100
28+33+30+40
46,5%
CALCULATION FOR
PHV
240
Ta+Tc
%F= x100
Ta+Tc+Tp+Ti
39+45
%F= x100
39+45+30+40
54.5%
CALCULATION FOR
PHV
360
TIM
E (
H
OU
R
S
)
PHV
2
4
0
PHV
36
0
CONCLUSION: Once obtained data has been applied to
graph1, the maximum time of use for model 240 is 2h:15min
and for 360 is 1h:30min.
Considering the quotas, model 240 should be used.
4 of 10
E.G. Model 360
E.G. Model 240
Graph.1
Graph.2
0
1h
2h
FREQUENCY OF USE
The curve below allows calculation of the maximum working time (T) depending on the frequency of use (F).
To ensure correct operation of the equipment the working time should be within the shaded area.
These trials have been carried out at a temperature of 22ºC. If the equipment is operating at a higher temperature or is
exposed to direct solar radiation, the frequency of use can be reduced by 20%.
%F : use factor
Ta : opening time
Tc : closing time
Tp : pausing time
Ti : time between complete operations
(opening-closing)
Ta+Tc
%F= _______________ x100
Ta+Tc+Tp+Ti
WORK AREA
Ed1. 14/12/09 (
English)
