71M6534H Demo Board User’s Manual
Page: 42 of 86
© 2005-2007 TERIDIAN Semiconductor Corporation
V2-0
From the voltage measurement, we determine that
1.
Î
1
+
=
V
XV
E
A
We use the other two measurements to determine
φ
S
and A
XI
.
2.
1
)
cos(
1
)
0
cos(
)
0
cos(
0
−
=
−
−
=
S
XI
XV
S
XI
XV
A
A
IV
A
A
IV
E
φ
φ
2a.
)
cos(
1
0
S
XI
XV
E
A
A
φ
+
=
3.
1
)
60
cos(
)
60
cos(
1
)
60
cos(
)
60
cos(
60
−
−
=
−
−
=
S
XI
XV
S
XI
XV
A
A
IV
A
A
IV
E
φ
φ
3a.
[
]
1
)
60
cos(
)
sin(
)
60
sin(
)
cos(
)
60
cos(
60
−
+
=
S
S
XI
XV
A
A
E
φ
φ
1
)
sin(
)
60
tan(
)
cos(
−
+
=
S
XI
XV
S
XI
XV
A
A
A
A
φ
φ
Combining 2a and 3a:
4.
)
tan(
)
60
tan(
)
1
(
0
0
60
S
E
E
E
φ
+
+
=
5.
)
60
tan(
)
1
(
)
tan(
0
0
60
+
−
=
E
E
E
S
φ
6.
Î
⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
+
−
=
−
)
60
tan(
)
1
(
tan
0
0
60
1
E
E
E
S
φ
and from 2a:
7.
Î
)
cos(
1
0
S
XV
XI
A
E
A
φ
+
=
Now that we know the A
XV
, A
XI
, and
φ
S
errors, we calculate the new calibration voltage gain coefficient from the
previous ones:
XV
NEW
A
V
CAL
V
CAL
_
_
=
We calculate PHADJ from
φ
S
, the desired phase lag:
[
]
[
]
⎥
⎦
⎤
⎢
⎣
⎡
−
−
−
−
−
−
−
+
=
−
−
−
−
)
2
cos(
)
2
1
(
1
)
tan(
)
2
sin(
)
2
1
(
)
2
cos(
)
2
1
(
2
)
2
1
(
1
)
tan(
2
0
9
0
9
0
9
2
9
20
T
f
T
f
T
f
PHADJ
S
S
π
φ
π
π
φ
Содержание 71M6534H
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