II. INSTALLATION
CAUTION:
All external wiring must comply with applicable codes and local ordinances.
DO NOT connect power supply until air cleaner has been installed and/or checked.
A. HOW TO DETERMINE THE NUMBER OF ELECTRONIC AIR CLEANERS
REQUIRED
To determine the number of electronic air cleaners required for your business
establishments, use the method below as a guideline. If you have any questions,
call the LakeAir HOTLINE at 1-800-558-9436 and we will help you.
METHOD: SIZE BY ROOM VOLUME AND AIR CHANGES PER
HOUR
1.
Calculate the volume of the room. Volume (cubic feet) = Length x Width x Height
2.
Determine the circulation of the air needed, based upon 8 air changes per hour for
average conditions, to reduce the smoke and pollution. Use 16 air changes per hour for
high concentrations of smoke and contaminants, or when one has a desire to reduce smoke
and pollution even further.
3.
The LA
2000
and 2000
-OC
have differing capacities in cubic feet/minute. Both models
are two speed units with a high and a low speed of operation. The LA
2000-oc
produces 800
cfm at low speed and 1
2
00 cfm at high speed. The LA2000 produces 1
6
00 cfm at low
speed and 2
0
00 cfm at high speed. To establish the correct unit and/or number of units to
use, you should calculate the cubic feet of air in the area to be cleaned, and then use a figure
of 8 air changes/hour in that area for average cleaning, and 16 air changes per hour for very
polluted or smoke filled conditions. You should remember that the slower the air passes
over the surface of the air cleaner, the more efficiently the unit will operate. Therefore,
when calculating the number of units needed, take into account air flow and cleaning
capacity.
EXAMPLE #1
ROOM DIMENSIONS:
TYPE OF AREA:
50’ X 100’ X 10’ CEILING
RESTAURANT OR LOUNGE
AIR CHANGES DESIRED: 16/HOUR
STEP 1 -
VOLUME =50’ X 100’ X 10’ = 50,000 CU. FT.
STEP 2
-
VOLUME TO BE CLEANED = 50,000 CU. FT. X 16 AIR CHANGES/HOUR
STEP 3 –
VOLUME/MINUTE TO BE CLEANED = 800,000 CU.FT./HOUR = 13,333 CU.FT. MIN.(CFM)
60,000
MINU
TES/HOUR
STEP 4 –
NUMBER OF UNITS NEEDED = 13,333 CFM
÷
THE CFM OF THE CHOSEN UNIT
(MODEL LA-2000) =13,333 CFM = 6.34 OR 6 UNITS
2,100 CFM
(MODEL LA-1400) =13,333 CFM = 12.09 OR 12 UNITS
1,100 CFM
EXAMPLE #2
ROOM DIMENSIONS:
TYPE OF AREA:
50’ X 30’ X 10’ CEILING
OPEN OFFICE AREA WITH MULTIPLE PERSONNEL
AIR CHANGES DESIRED: SOME SMOKERS AND 20 DESKS – USE 8 AIR CHANGES/HOUR
STEP 1 –
VOLUME = 50’ X 30’ X 10’ = 15,000 CU.FT.
STEP 2 –
VOLUME TO BE CLEANED = 15,000 CU.FT. X 8 AIR CHANGES/HOUR = 120,000 CU.FT./
HOUR
STEP 3 –
VOLUME/MINUTE TO BE CLEANED = 120,000 CU.FT./HOUR = 2,000 CU.FT./MINUTE(CFM)
60 MINUTES/HOUR
STEP 4 –
NUMBER OF UNITS NEEDED = 2,000 CFM DIVIDED BY THE CFM OF THE CHOSEN UNIT
(MODEL LA-2000)
(MODEL LA-1400)
= 2,000 CFM = 1 UNIT
2,100 CFM
= 2,000 CFM = 1.8 OR 2 UNITS
1,
CFM
100
