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30
462
1A
1B
1CLR
1Q
2Q
2CX
2RX/CX
GND
VCC
1RX/CX
1CX
1Q
2Q
2CLR
2B
2A
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
+5V
+5V
74HC123
221k
+
1µF 25V
Step Clock
IB462H Pin 4
BSS123
0.1µF
R
Red
R
Adj
2k
Current Adjust
IB462H Pin 1
+5V
0.1µF
V
Ref
WARNING!
Do not exceed 1.0 volts on the Current Adjust
Input!
R e d u c i n g t h e O u t p u t C u r r e n t
Figure 1.7.2 below illustrates a simple circuit which can be used to automati-
cally reduce the current in the motor windings after a move. Using this will
greatly reduce the amount of motor and drive heating in your system.
The amount of current reduced will depend upon the value of the Reduction
Adjust Resistor (R
Red
) and the value of the Current Adjust Resistor (R
Adj
) .
The Current will be reduced 200 msec after the rising edge of the last Step
Clock Pulse. The values of R
Red
and R
Adj
are calculated as follows:
Figure 1.7.2: Current Adjust/Reduction Circuit
I
Run
is the desired running
current. Range 0.1A to 2A per
Phase.
I
Hold
is the desired holding
current. Range 0A to 2A per
Phase.
NOTE!
These equations ONLY apply to the circuit example below. If
using the IB462H with an INT-462 see Section 2.1:
The INT-462,
for
details on adjust and reduction resistor values.
I
Run
R
Adj
= 2000 x
(10 - I
Run
)
I
Run
x I
Hold
R
Red
= 2000 x
(I
Run
- I
Hold
)