Citizen C460, Инструкция по эксплуатации

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31 30
10) Conversion
Example
: Convert 30 statute miles into nautical miles and kilometers.
Operation : Align "30" on the outer scale with STAT (
▲
) on the inner scale. Then, NAUT
(
▲
) on the inner scale corresponds to "26" nautical miles on the outer scale,
and km (s) on the inner scale corresponds to "48.2" km on the outer scale.
11) Fuel conversion
Example
: Convert 16.8 U.S.gallons into liters.
Operation : Align"16.8"on the inner scale with U.S GAL.(
▲
)on the outer scale. Then,
LITERS.(
▲
)on the outer scale corresponds to "63.5" liters on the inner
scale.(1 U.S.gallon=3.78541 liters)
The same method can be applied to the conversions of U.S. gallons
→
IMP.
gallons / liters
→
U.S. gallons / liters
→
IMP. gallons / IMP. gallons
→
U.S.
gallons / IMP. gallons to liters.
12) Volume - weight conversions (fuel pounds to U.S. gallons, U.K. gallons and liters)
Example
: Convert 13. 1 fuel pounds into U. S. gallon, IMP. (imperial)gallons and liters.
(1 fuel pound=0. 167 U. S. gallon=0. 139 IMP. gallon=0. 632 liters)
Operation : Align"13. 4"on the inner scale with FUEL LBS. (
▲
)on the outer scale. Then,
U. S. GAL. (
▲
)on the outer scale corresponds to"21. 8(2. 18 U. S. gallons)"on
the inner scale. Then, IMP. GAL. (
▲
)on the outer scale corresponds to "18.
2(1. 82 IMP. gallons)"on the inner scale, and LITERS. (
▲
)on the outer scale
corresponds to"82. 7(8. 17 liters)"on the inner scale.
7) Difference in altitude
The difference in altitude can be obtained from the descent rate and the descent time.
Example : Obtain the difference in altitude when an aircraft continues descending for 23
minutes at a rate of 250 feet per minute.
Answer : Align "25" on the outer scale with "10" on the inner scale. Then, "23" on the inner scale
corresponds to "57.5" on the outer scale. Thus, the difference in altitude is 5,750 feet.
8) Rate of climb (or descent)
The rate of climb (or descent) can be obtained from the time required to reach an altitude.
Example : Obtain the rate of climb when an aircraft reaches an altitude of 7,500 feet
after climbing for 16 minutes.
Answer : Align "75" on the outer scale with "16" on the inner scale. Then, "10" on the
inner scale corresponds to "47" on the outer scale. Thus, the rate of climb is
470 feet per minute.
9) Time of climb (or descent)
The time required for climb can be obtained from the altitude to be reached and the rate
of climb (or descent) .
Example : Obtain the time of climb when an aircraft is to climb to 6,300 feet at a rate of
550 feet per minute.
Answer : Align "55" on the outer scale with "10" on the inner scale. Then, "63" on the
outer scale corresponds to "11.5" on the inner scale. Thus, the time of climb is
11 minutes and 30 seconds.