INSTALLATION
5
Parallel operation requires a maximum of
two thirds of the motor's rated per phase
current.
Series operation requires a maximum of one
third the motor's rated per phase current.
Use the manufacturer's phase current rating for the motor and the motor wiring
configuration (high or low performance) to estimate the size of power supply required.
As an example, a six lead motor rated by the manufacturer at four amps per phase is
connected in the full winding (series) configuration. To calculate the current required
from the power supply use Equation 2. Assume a transformer with a 25 volt RMS
secondary is used. After rectification the transformer will produce a 37 VDC power
supply voltage. To calculate the size of the filter capacitor (C1) use the following
equation:
(
)(
) (
)(
)
f
f
V
I
C
SUPPLY
SUPPLY
μ
μ
3000
48
.
2995
37
33
.
1
333
,
83
333
,
83
1
≈
=
=
=
Equation 3 - Power Supply filter capacitor
C2 (
X
Figure 3
X
, page
X
4
X
) is the 470 µf capacitor located close to the CN0165’s power
supply terminals. C1 may be made smaller by that amount if desired. Both capacitors
must have a voltage rating safely in excess of the power supply voltage, 50 VDC in this
example.
More than one CN0165 may be run from a common power supply if the filter capacitor
is large enough to handle the combined load of the drives. Each CN0165 must have
separate power leads to the supply. Do not daisy-chain power leads from supply to
driver to driver.
I
SUPPLY
=
2/3
x
I
PHASE
Equation 1 - Drive Current (Parallel)
I
SUPPLY
=
1/3
x
I
PHASE
Equation 2 - Drive Current (Series)
Содержание CN0165
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