7
Load - Pressure Correlation For Model J50040 & J50100
Always monitor the force applied to workpiece by using a load cell and indicator or you may monitor pressure developed
in the ram by using an inline pressure gauge, then calculate the applied force using the formula:
F = P x A
For model J50040,
A
= 0.998 in² ;
For model J50100,
A
= 2.411 in²
Example1
Model J50040 lifting 5,000 lbs will require what pressure?
Pressure
= 5,000 lbs / 0.998 in² = 5,010 psi
where F = Force/ Load (lbs);
P = Hydraulic working pressure (psi) and;
A = Ram effective area (in²)
Example2
Model J50100 operating at 6,000 psi will generate what force?
Force
= 6,000 psi x 2.411 in
2
= 14,466 lbs
Load
(lbs)
Pressure of 4 Ton Ram,
where A = 0.998 in
2
(psi)
Pressure of 10 Ton Ram,
where A = 2.411 in
2
(psi)
1,000
1,002
415
2,000
2,004
830
3,000
3,006
1,244
4,000
4,008
1,659
5,000
5,010
2,074
6,000
6,012
2,489
7,000
7,014
2,903
8,000
8,016
3,318
9,000
3,733
10,000
4,148
11,000
4,562
12,000
4,977
13,000
5,392
14,000
5,807
15,000
6,221
16,000
6,636
17,000
7,051
18,000
7,466
19,000
7,881
20,000
8,295
