ADTRAN 1245001L6, Руководство по установке и обслуживанию

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61245001L6-5G Section 61245001L6-5, Issue 7 17
Power Consumption
The ADTRAN 5
th
Generation Low Voltage E220
HTU-C M R current requirements vary depending
on the number of span powered units included in the
HDSL circuit. The configuration aid in
Table 9 can
be used to determine maximum allowable shelf fill,
while maintaining appropriate current drain.
7. TROUBLESHOOTING PROCEDURES
Table 10
is a troubleshooting guide for the 220/
E220 HTU-C M R.
8. MAINTENANCE
The ADTRAN 220/E220 HTU-C M R requires no
routine maintenance. In case of equipment
malfunction, use the faceplate Bantam jack
connectors to help locate the source of the problem.
ADTRAN does not recommend that repairs be
performed in the field. Repair services may be
obtained by returning the defective unit to the
ADTRAN Customer Service RMA Department.
Condition
All front panel indicators are off .
Solution
1. Verify that -48 Vdc power is properly connected to the
shelf.
2. Insert the HTU-C M R into an operational slot and check
the LED indicators. When the unit is powered, at least
one LED will be
on .
3. If Step 1 passes, but Step 2 fails, replace the HTU-C.
Table 10. Troubleshooting Guide
Table 9. Power Consumption Worksheet
Step 1 Enter size of fuse for shelf (Amps) ..........................................................................................
(Size required for over current protection (i.e., 100%, 75%, 50%) .........................................
Step 2 Determine the mix of HDSL circuits in shelf.
Percentage of circuits with an HTU-R only .............................................................................
Percentage of circuits with one HRE and an HTU-R ..............................................................
Percentage of circuits with two HREs and an HTU-R ............................................................
Step 3 Determine the current draw of the HDSL circuits.
Multiply (C) by 0.2 Amps (with no HRE) ...............................................................................
Multiply (D) by 0.3 Amps (with one HRE) .............................................................................
Multiply (E) by 0.51 Amps (with two HREs) ..........................................................................
Step 4 Add (F) through (H) to get total current draw .........................................................................
Step 5 Divide (B) by (I) to get the number of units per shelf .............................................................
(A) _____ Amps
(B) _____ Amps
(C) _____ %
(D) _____ %
(E) _____ %
(F) _____ Amps/unit
(G) _____ Amps/unit
(H) _____ Amps/unit
(I) _____ Amps/unit
_____ Units/shelf*
* If the number of units/shelf is greater than or equal to the shelf’s slot availability, full shelf population is allowable.