Acson international ACC 10CW, Руководство пользователя

Страница: 87 / 172

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Step 2
From page 53 , the air flow correction factor table, at high speed, the air volume is 1040 CFM and medium
speed is 950CFM, hence high speed is selected. And the correction factor is hence 1.0.
If lower air flow required, then use the medium and low fan speed. The correction factor can be determined by
getting the ratio of air flow (i.e. medium or low speed / high speed).
Step 3
As the unit is operating at 600m above sea level, the Altitude correction factor is 0.98 total and 0.93 sensible.
Step 4
Multiply the cooling capacities obtained from step 1 (as per specification and design condition) by correction
factors from (2) and (3)
Actual total cooling capacity = 11.7 x 1.0 x 0.98 kW = 11.47 kW
Actual sensible cooling capacity = 8.5 x 1.0 x 0.93 kW = 7.91 kW
Step 5
Water flow rate = Litres/M =
11470 W
= 32.8
70 x 5
Step 6
From Heating Capacity Performance Chart (Page 13
2
) , determine the heating capacity at the nominal air
volume by using the flow rate calculated in step 5. The heating capacity is at 20.6 kW.
Step 7
From Heating Capacity Correction Factor Tables at 70°C water entering temperature and 26.7°C entering air
temperature, the correction factor is 1.1261,
Actual Heating Capacity = 20.6 x 0.98 x 1.1261 = 22.7 kW
Step 8
Water Pressure Drop can be estimated from water Pressure Drop Table (Page 47 to 52) using interpolate
method:
At flow rate of 32.8 Litres/Min, the nominal pressure drop is 39.14 kPa
Pressure drop correction factor = 1.2947 - 0.0021 x (EWT°C x 1.8 + 32) = 0.9629
Hence the actual pressure drop = nominal pressure drop x correction factor = 37.69 kPa.
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Water Flowrate - L/min
Heatin
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