Zeta Alarm Systems SIMPLICITY MICRO, Instruction Manual, Page: 23 / 28

ADDRESSABLE
FIRE ALARM PANEL
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INSTRUCTION MANUAL: 32 Device,4 Zone Addressable Fire Alarm Panel
Approved Document No: GLT.MAN-129
PAGE 23
Issue : 1.0 Author: NRPJ Date: 11/04/2008
Battery Calculation
Here are the current consumption of the Simplicity Micro panels in various
conditions:-
Control Panel Model
Mains Fail,
buzzer sounding Mains Fail,
buzzer silenced Mains fail,
panel in alarm
Simplicity Micro 39mA 37mA 65mA
Sample Calculation
A Simplicity Micro panel has the following items connected:-
Zone 1: 1 x MCP, 2 x Optical Detector, 2 x Sounder base
Zone 2: 1 x MCP, 1 x Optical Detector, 1 x Sounder base
Zone 3: 1 x Heat Detector, 1 x Sounder base
Zone 4: 2 x Optical Detector, 2 x Sounder Flasher base
ITEM QUIESCENT ALARM
SIMPLICITY MICRO 39mA (in fault) 65mA
MCP 1.0mA 3.5mA
OPTICAL 100uA 12mA
HEAT 50uA 12mA
SOUNDER BASE
1.2mA 5.5mA
SOUNDER FLASHER BASE 1.2mA 7mA
To calculate the required battery backup required, we use the equation:-
Battery Size (Standby time in Amp Hours) = 1.25 x [(T
ALM
x I
ALM
) + (T
SBY
x I
SBY
)]
Where:
T
ALM
= Maximum time in hours required for the alarm [½ hour is most common time]
I
ALM
= Total Alarm Current in amps for all alarm devices connected to the alarm circuits
T
SBY
= Standby time in hours for the system after mains failure [normally 24, 48 or 72 hr]
I
SBY
= Quiescent current in amps of control panel in fault condition [because of mains failure]
PLUS all loop devices.
I
ALM
= (
SIMPLICITY MICRO) ALM + (4 X SOUNDER BASE ALARM) + (2 X SOUNDER FLASHER
BASE ALARM) + (1 X DETECTOR ALM) + (2 X MCP QU) + (4 X OPT QU) + (1 x
HT QU)
=0.065 + 4x 0.0055 + 2x 0.007 + 1x0.012 + 2x0.001 + 4x0.0001 + 1x0.00005
=0.065 + 0.022 + 0.014 + 0.012 + 0.002 + 0.0004 + 0.00005
=0.11545 Amps
I
SBY
= (SIMPLICITY MICRO QU) + (4 X SOUNDER BASE QU) + (2 X SOUNDER FLASHER BASE
QU) + (2 X MCP QU) + (5 X OPT QU) + (1 x HT QU)
=0.039 + 4x0.0012 + 2x0.0012 + 2x0.001 + 5x0.0001 + 1x0.00005
=0.039 + 0.0048 +0.0024 + 0.002 + 0.0005 + 0.00005
=0.04875
Therefore:-
Battery size
= 1.25 X ((0.5 x 0. 0.11545) + (24 x 0.04875))
= 1.25 X (0. 1.17)
= 1.25 x 1.227725
= 1.5346 Ah
So 2.0 Ah batteries will be suitable for this installation.