![background image](http://html1.mh-extra.com/html/smc-networks/pte-50-cet/pte-50-cet_instruction-manual_1300981027.webp)
PTE-50-CET
Sheet 26
3.4.3. EXAMPLE
Suppose we want to inject 65 A to a relay using the three channels in parallel. After making the
connections, we will select:
CH
1
→
Amplitude: 22 A
Phase angle: 0.0º
CH
2
→
Amplitude: 22 A
Phase angle: 0.0º
CH
3
→
Amplitude: 21 A
Phase angle: 0.0º
Now we can have 300 VA as maximum, so the current we can get from the equipment will depend on
the connected load. As we don’t know this impedance load of the relay, we will calculate the
maximum load that can be connected to the taps injecting 65 A:
VA
OUTPUT
= I
OUTPUT
×
V
OUTPUT
Z
LOAD
= V
OUTPUT
/ I
OUTPUT
⇒
VA
OUTPUT
= I
OUTPUT
2
×
Z
LOAD
Then if we are looking for the maximum load at 65 A:
Z
MAXIMUM LOAD
= VA
MAXIMUM OUTPUT
/ I
OUTPUT
2
= 300/65
2
= 0.071
Ω
If we connect a relay with higher impedance than 0.071
Ω
(considering PTE-50-CET as an ideal
generator), it will be an overload for the PTE-50-CET. The equipment will stop the injection, indicating
the
Overload Alarm
.
3.5.
GENERAL CONTROL SECTION
This part of the equipment refers to the general control. The unit
contains several necessary controls to perform the following functions:
•
Using
RS-232.
•
SYNCHRONIZE
selection.
•
HARMONICS
selection.
•
BOOSTER
activation.
•
EVENT
Output.
•
Monitor
signals.
•
BUS-PTE
interconnection.