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ICP-S Technical Manual 

 

Overcurrent Protection Elements

  

Rev.A 

7/13 

 

7.  ICP-S Test Example

7-1 Example 1

Current mode: DC

Model: ICP-S1.0

Wave form:

DC

1A

2A
5A

Test:

The current values of all segmented periods are plotted respectively as shown in attached graph 1.

1 A: The steady-state current is in the safety area where the ICP-S will not deteriorate or break the current.

2 A: The ICP-S will break the steady-state current in the breaking current area in approximately 100 ms.

5 A: The ICP-S will break the steady-state current in the breaking current area in approximately 0.7 ms.

7-2 Example 2

Current mode: A single pulse

Model: ICP-S1.0

Wave form: A current of 1.75 A flows for a period of 20 ms.

Results: The steady-state current is in the critical area. If the single pulse is repeated intermittently, 

the ICP-S will deteriorate or break the current in the end.

Test:

With pulse current: I

2

t = 1.75

2

×

20

= 61 (A

 ms)      at 20ms     (See graph 2)

20ms

1.75A

 

 
 
 
 

Summary of Contents for ICP-S

Page 1: ...2 0 0 05 1 75 0 1 4 0 0 1 0 4 0 1 0 0 1 1 8 0 1 0 6 1 0 3 2 0 2 2 0 0 1 1 55 0 1 2 5 0 1 3 0 0 1 0 1 0 1 5 TN direction 3 Features 1 Instantly breaks currents with a low potential drop See 3 1 Potenti...

Page 2: ...ent Protection Elements Rev A 2 13 3 1 Potential Drop Comparison ICP S VS Fuse ICP S1 0 Rated Current 1 A 2 0A 1 8A 1 5A 1 0A DC 500mV div NORMAL 10mSEC div Fuse Rated Current 1 A 4 0A 3 0A 2 0A 1 0A...

Page 3: ...ata ICP S1 0 n 5pcs 5lot typ max min 50 0 0 7 0 8 0 9 1 0 1 1 1 2 Ambient temperature Ta C Breaking current ratio 25 0 25 50 75 100 125 Breaking Current vs Ambient Temperature Characteristics ICP S 0...

Page 4: ...rrent of the ICP Is the rated voltage i e the open circuit voltage when the ICP breaks the current 50 V or below Is the breaking current the maximum abnormal current within a range of 2x to 10x of the...

Page 5: ...del with higher ratings Note The inspection and selection of the ICP according to the Joule integral value is absolutely based on the results of the approximation of the current wave form Be sure to i...

Page 6: ...ariety of wave forms The charged wave form is segmented as shown below The Joule heat generated during each segmented period is plotted onto a Joule integral sheet 1 Triangular wave form 0 t Im I2 t I...

Page 7: ...t 2 A The ICP S will break the steady state current in the breaking current area in approximately 100 ms 5 A The ICP S will break the steady state current in the breaking current area in approximately...

Page 8: ...no margin C Effective pulse recommended critical line with margin 0 001 0 01 0 1 1 10 100 1000 10000 0 01 Time msec I 2 t A 2 ms 0 1 1 10 100 1000 10000 100000 I2 t t Characteristic Curve ICP S1 0 Gra...

Page 9: ...necting the peak of each current wave form Test Obtain the approximated value by substituting the values into the formula triangular wave form I2 t 1 3 Im2 t I2 t 1 3 32 A 1ms 3 A2 ms Plotting test Te...

Page 10: ...l wave form Approximation curve for Joule integral calculation 10A 8A 6A 2A 3 5A 0 1ms 0 35ms 0 25ms 0 55ms 0 06ms Item Peak current Im A t ms ms A2 ms Formula Coefficient Im2 t A2 ms No 1 10 0 06 0 0...

Page 11: ...0 seconds min 230 C 260 C 150 200 250 300 0 50 100 C Preheating speed A peak temperature of at least 230 C is recommended If the peak temperature is less than 230 C it is recommended to make some adju...

Page 12: ...ICP S Technical Manual Overcurrent Protection Elements Rev A 12 13 9 Application Circuit Examples 9 1 Power Supply Circuit 9 2 DC DC Converter 9 3 Motor Control ICP ICP ICP M ICP VCC...

Page 13: ...Effective pulse critical line with no margin C Effective pulse recommended critical line with margin 0 001 0 01 0 1 1 10 100 1000 10000 0 01 Time msec I 2 t A 2 ms 0 1 1 10 100 1000 10000 100000 I2 t...

Page 14: ...tion to the peripheral conditions when designing circuits and deciding upon circuit constants in the set Any data including but not limited to application circuit diagrams information described herein...

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