Euro-C 4000-JLGBEN
27/31
1
1
min
1
2
+
−
×
=
Q
Q
x
x
Q
Q
tot
tot
HS
s
m
Q
HS
/
³
508
,
0
1
1
4
,
0
1
465
300
1
=
+
−
×
=
To calculate this air flow, following
interpolation rule should be applied :
With
Q
min
=
Minimal recommended air flow
(Table
2)
(m³/s)
Q
tot
=
Total Air Flow (m³/s)
x
1
=
Recommended By-Pass width
(from figure 16 to 19) (mm)
x
2
= Applied by-pass width (mm)
Then Q
HS
(air flow over heating section) can be
calculated as :
As explained above, the air flow Q
HS
over the
heating section must be used in figures 13 to
19, to extract the correct pressure drop over
the heat exchanger.
Example : Application on Euro-C 4011
RJL/DJL, By-Pass = 300 mm wide x 310 mm
high, Total Air Flow 1 m³/s.
From table 2, the minimal air flow for this unit
is 1465 m³/h, corresponding to 1465/3600 or
0,4 m³/s.
The recommended by-pass width for this air
flow is 465 mm (x
1
).
Filling in all these values in above formula
results in
Figure 16 : EURO-C 4000
Model
Dim. A
Dim. B
Dim. C
Dim. D
4011
4015
4018
4024
4030
4036
4047
4060
4072
4100
310
410
480
480
550
696
836
696
836
900
490
490
490
620
620
620
620
950
950
1800
To be calculated as per
section 11.2
Summary of Contents for EURO-C 4000 DJL
Page 5: ...Euro C 4000 JLGBEN 5 31 Figure 1 Dimensions EURO C 4011 15 RJL DJL Fig 1 A Fig 1 B...
Page 6: ...Euro C 4000 JLGBEN 6 31 Fig 1 C...
Page 7: ...Euro C 4000 JLGBEN 7 31 Figure 2 Dimensions EURO C 4018 72 RJL DJL Fig 2 A Fig 2 B...
Page 8: ...Euro C 4000 JLGBEN 8 31 Fig 2 C...
Page 9: ...Euro C 4000 JLGBEN 9 31 Figure 3 Dimensions EURO C 4100 RJL DJL Fig 3 A Fig 3 B...
Page 10: ...Euro C 4000 JLGBEN 10 31 Fig 3 C...
Page 18: ...Euro C 4000 JLGBEN 18 31 Figure 8a models 4011 72 Figure 8b model 4100...
Page 19: ...Euro C 4000 JLGBEN 19 31 Figure 8c all models Figure 9a models 4011 72...
Page 22: ...Euro C 4000 JLGBEN 22 31 Figure 10b MODELS 4011 72 MODEL 4100...
Page 24: ...Euro C 4000 JLGBEN 24 31 Figure 12 Models 4011 72 Model 4100...
