S8EA
16
Mounting
• Install the Power Supply so that heat is effectively dissipated to
improve and maintain the reliability of the Power Supply over a
long period of time.
• The S8EA uses natural convection. Mount so that convection of
the air around the power unit can take place.
• The crosshatching indicates the allowable range for the mounted
metal part.
• When mounting, use the mounting holes in the board and spacers
to mount at least 8 mm off the board. This a clearance of 4 mm
space is necessary to satisfy the insulation and withstand voltage
standards.
• Metal plate is strongly recommended as the mounting panel.
Note: 1.
Do not subject the board to stress such as twisting, bending,
or shock. This may cause failure or deterioration.
2.
During assembly, do not subject the lead feet or surface
mounted parts to stress. This may cause failure or
deterioration.
• Depending on how the Power Supply is mounted, the heat
dissipating capacity may be reduced and cause deterioration to or
damage the internal components.
• The internal parts may occasionally deteriorate and be broken due
to adverse heat radiation. Do not loosen the screws on the Power
Supply.
Output Voltage Adjuster (V. ADJ)
Default Setting: Set at the rated voltage.
Adjustment Range: The output voltage can be adjusted to ±10% of
the rated voltage with the voltage output adjuster
(V. ADJ) on the front panel.
Turning clockwise increases the output voltage,
and turning counterclockwise decreases the
output voltage.
• The output voltage adjuster (V. ADJ) may possibly be damaged if
it is turned with unnecessary force. Do not turn the adjuster with
excessive force.
• After completing output voltage adjustment, be sure that the output
capacity or output current does not exceed the rated output
capacity or rated output current.
• Adjusting the output voltage adjuster (V. ADJ) may cause the
output voltage to exceed the voltage range. When adjusting the
output voltage, check the output voltage of the Power Supply and
be sure that the load is not destroyed.
Series Operation
Two Power Supplies can be connected in series. The ± voltage output
can be accomplished with two Power Supplies.
Note: 1.
If the load is short-circuited, a reverse voltage will be
generated inside the Power Supply. If this occurs, the
Power Supply may possibly deteriorate or be damaged.
Always connect diodes as shown in the figure. Select
diodes with the following ratings.
2.
Although Products having different specifications can be
connected in series, the current flowing through the load
must not exceed the smaller rated output current.
Parallel Operation
The Product is not designed for parallel operation.
However, the following backup operation is possible. (External diodes
are required.)
Use the same model for Power Supplies A and B.
• Set the output voltages of Power Supplies A and B higher to
compensate for the decrease of the forward voltages (V
F
) of diodes
D1 and D2.
Also, there will be a power loss equivalent to the output current
(I
OUT
) of the Power Supply multiplied by the forward voltage (V
F
) of
the diode. Therefore, cooling will be required to keep the
temperature of the diodes lower than the catalog value.
• There will be a power loss caused by load power and diodes. Be
sure not to exceed the rated power (rated output voltage times
rated output current) of each Power Supply.
Precautions for Correct Use
Mountin
g
Interval
CN1
4 mm min.
8
mm min.
4 mm min.
4 mm min.
CN1
4 mm min.
4 mm min.
Locations of Mountin
g
Holes on Open-frame Models
8
mm
8
mm
8
mm
8
mm
8
mm
8
mm
8
mm
8
mm
CN1
Type
Schottky Barrier diode
Dielectric strength
(V
RRM
)
Twice the rated output voltage or above
Forward current (I
F
)
Twice the rated output current or above
• Type: Schottky barrier diode
• Dielectric strength (V
RRM
): Rated output voltage of the Power
Supply or higher
• Forward current (IF): Twice the rated output current of the Power
Supply or higher
+
V
−
V
AC(L)
AC(N)
AC(L)
AC(N)
+
V
−
V
+
V
−
V
AC(L)
AC(N)
AC(L)
AC(N)
+
V
−
V
Series Operation
Correct
Output Voltage (±)
Correct
+
V
−
V
AC(L)
AC(N)
AC(L)
AC(N)
+
V
−
V
Parallel Operation
Incorrect
+
V
A
B
D
1
D
2
−
V
+
V
−
V
Load
