Electra ECF12 DCI INV, Technical Manual, Page: 42 / 88

K DCI
PXD DCI
LS DCI
PERFORMANCE DATA
5.14 Model Correction Factors (F
M
)
Model
Capacity Power input
Cooling Heating Cooling Heating
WNG DCI 1.00 1.00 1.00 1.00
ECF
DCI
1.03 1.07 1.01 1.10
PXD DCI TBD TBD TBD TBD
LS DCI TBD TBD TBD TBD
15.15 Calculation Example
Outdoor Unit
Quattro DCI
Indoor Combination WNG
9
+WNG
12
+
ECF12
+WNG
18
Operation Mode Cooling Mode
Conditions Indoor
22
°
CDB/15
°
WB
Conditions Oudoor
30
°
CDB
Tubing length
20m+10m+5m+25m
Cooling Capacity calculation:
C
A-D
[KW] = Nominal x F
M
x F x F
T C
Total System Capacity [KW] (TC) = C
A
+ C + C
C
+ C
B D
Indoor Unit
Nom’ Cooling
Capacity
[KW]
Model
Factor
(F
M
)
Condition
Factor
(F
C
)
Tubing(L)
Factor
(F
T
)
Corrected Capacity
[KW], (C
A-D
)
Room A – WNG
9
1.43 1.00 0.92 0.95 C
A
= 1.43x1.00x0.92x0.95= 1.25
Room B – WNG
12
1.91 1.00 0.92 0.985 C
B
= 1.91x1.00x0.92x0.985= 1.73
Room C –
ECF12
1.91 1.03 0.92 1.00 C
C
= 1.91x1.03x0.92x1.00= 1.81
Room D – WNG
18
2.87 1.00 0.93 0.93 C
D
= 2.87x1.00x0.93x0.93= 2.48
Total TC =1.25+1.73+1.81+2.48= 7.27
Cooling Power Input calculation:
P
A-D
[KW] = Nominal x F
M
x F
C
x F
T
Total System Power Input [W] (TP) = P
A
+ P
B
+ P
C
+ P
D
Indoor Unit
Nom’ Cooling
Power Input
[W]
Model
Factor
(F
M
)
Condition
Factor
(F
C
)
Corrected Power Input [W]
(P
A-D
)
Room A – WNG
9
1.00 0.88 P
A
= 602.5 x 1.00 x 0.88 = 530
Room B – WNG
12
1.00 0.88 P
B
= 602.5 x 1.00 x 0.88 = 530
Room C –
ECF12
2,410 / 4 = 602.5
1.01 0.88 P
C
= 602.5 x 1.01 x 0.88 = 535
Room D – WNG
18
1.00 0.86 P
D
= 602.5 x 1.00 x 0.86 = 518
Total TP = 530 + 530 + 535 + 518 = 2,113
5-26 Revision
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