
Page 30
of
18
ohms,
and
remembering
that
power
is
P
=
I
2
*
R,
the
carrier
power
is
thus
0.273*
0.273
*
18
=
1.34W.
The
voltage
that
must
be
developed
to
support
this
current
is
given
by
P
=
E
*
I,
or
1.34
=
E
*
0.273,
and
thus
E
=
4.9Vrms,
or
14Vp
‐
p,
well
within
the
volt
‐
age
available
(twice
the
supply
or
22.2Vp
‐
p).
This
14Vp
‐
p
is
then
transformed
by
T3
to
23Vp
‐
p
driv
‐
ing
the
50
ohm
filter
load,
or
8.2Vrms.
Ignoring
the
small
power
loss
in
the
transformer,
the
available
power
is
8.2
2
/50
=
1.34W.
Assuming
Q3
has
a
gain
of
about
10,
a
14Vp
‐
p
output
re
‐
quires
a
1.4Vp
‐
p
input.
That
sig
‐
nal
comes
from
the
2N5109
output
stage,
which
was,
as
you
recall,
generating
a
6Vp
‐
p
signal.
Trans
‐
former
T2
stepped
it
down
by
a
factor
of
3
to
produce
the
needed
1.4Vp
‐
p
or
more.
Note
—
because
of
variations
in
transistor
beta,
your
voltages
may
vary
from
this
example
by
as
much
as
50%.
Total
power
in
an
AM
signal
with
100%
modulation
is
1.5
times
the
carrier
power,
so
a
carrier
power
of
1.34W
translates
to
a
total
AM
power
of
2W.
Note
that
it
took
about
4W
of
DC
power
to
create
this
(Vce
*
Ic
=
(11
‐
.58)*0.386),
resulting
in
an
efficiency
for
this
class
A
amplifier
of
50%.
The
output
low
pass
filter
is
a
7
‐
element
Elliptical
filter
with
a
cutoff
frequency
of
8MHz.
This
frequency
was
chosen
to
get
as
close
to
7.29MHz
as
possible
so
as
to
eliminate
harmonics
while
allowing
for
component
tolerances
so
that
the
inductors
and
capaci
‐
tors
do
not
have
to
be
adjusted.
Receiver
operation
When
the
PTT
switch,
S1,
is
in
the
receive
position,
supply
power
is
routed
to
the
receiver
circuits
and
not
to
the
transmit
‐
ter
circuits
(HT
‐
7
‐
2
board,
sheet
2
of
schematics;
11.1V
‐
>
RXV).
The
antenna,
after
passing
through
the
same
low
pass
filter
as
the
transmitter,
is
fed
through
a
high
pass
filter
with
a
cutoff
frequency
of
6
MHz.
This
keeps
local
AM
broadcast
and
many
shortwave
broadcast
stations
from
causing
interference.
The
result
‐
ing
6
‐
8MHz
signal
is
then
fed
to
FIN,
the
same
signal
path
taken
by
the
transmitter.
In
this
case,
Q1
serves
as
not
only
an
imped
‐
ance
matching
circuit
but
also
as
a
preamp.
The
output
of
Q1
is
then
fed
into
the
6kHz
crystal
filter
which
passes
only
the
6kHz
range
of
frequencies
centered
at
7.290MHz.
The
output,
FOUT,
is
fed
via
PTT
switch
S1
to
the
re
‐
ceiver
circuits
starting
at
RX
(HT
‐
7
‐
2
board,
sheet
3).
U1
and
U4
form
a
full
‐
wave
AM
de
‐
tector.
Most
AM
detectors
are
simple
half
‐
wave
diode
detectors.
This
circuit
was
first
proposed
Summary of Contents for HT-7
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