Example: (Using English System Units)
STEP 1:
Let’s assume the attic space on the previous page has a base (W) of 26 feet, and a height
(H) of 7 feet and a length (L) of 43 feet. The volume (V) may be determined as:
V=
26 x 7 x 43 = 3913 = 3900 cubic feet
2
Let’s also assume that the formulation label specifies a normal usage rate of 1 ounce per
3000 cubic feet. (Table 2)
Knowing the usage rate from the formulation label and the volume of space to be fogged, the
formulation volume and fogging time can be calculated as shown below.
STEP
#2:
The normal required formulation volume is:
1.3 ounces
(3900 cu. ft.) x (1 oz.) =
3000 cu. ft.
STEP #3
The normal time to fog 1.3 ounces is:
Where t = normal time to fog,
and 10 oz. is the average
machine flow-rate to achieve
a “dry fog”.
(1.3 oz.) x
(10 oz.)
(t seconds) (60 seconds)
t seconds = (60 seconds) (1.3 oz.) =
8 seconds
10 oz.
FOGGING OUTDOORS:
Read and follow all cautions and warnings for “Dispensing Fog” on pages
13 and 14. Read and follow the instructions for thermal fogging on the chemical solution label.
14
Summary of Contents for BLACKHAWK 2620
Page 1: ...MODEL 2620 2630 INSTRUCTION MANUAL FOR OPERATION SERVICE AND MAINTENANCE ...
Page 24: ...24 ...
Page 44: ... 12 86629 ASOV Assembly 12 ...
Page 48: ...Figure 43 43 ...