Appendix B. Processing Time Limitations
Example 3
Given:
N = number of channels measured
F = Frequency of input signal, kHz
Function = frequency (Function 2)
Output Option = XXXX with specified sampling interval, S
Find: Sampling interval, S, such that the number of unprocessed events is
d
8000
Solution: The interval required to process 8000 events after the sampling
interval is Tt-S, therefore;
(Tt-S)*F*N
d
8000
S
t
Tt-(8000/(F*N))
S
t
(0.511*S+Et*(.034+.010*N)+0.015*E2)
-(8000/(F*N))
Note:
E2 = Et = N*F*S
S
d
8000/[F*N((0.511+N*F*(0.49 +.01*N))-1)]
Results for the above example are presented in Table 3, Section 5.4.1
B-3