Chapter 1
13
Getting Started
Option 215 Limitations
Getti
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Example 3: Second Harmonic Sweep With a Sweep Offset
Suppose that you specify on your PSA Series analyzer that you wish to
perform a second harmonic sweep from 2.85 GHz to 3.00 GHz using 601
points, and an offset of 1.0 GHz. What is the actual range that the
signal source will sweep?
First of all, we need to work out our bucket size, or the bucket width.
This is given by the range in Hertz divided by (number of points minus
1), or
so
Now we can work out the external source’s start frequency using the
following equation:
Finally we can work out the external source’s stop frequency using the
following equation:
So if you specify on your PSA Series analyzer that you want to perform
a second harmonic sweep from 2.85 GHz to 3.00 GHz using 601 points
and a 1.0 GHz sweep offset, the signal source itself will actually sweep
from 1.924875 GHz to 2.000125 GHz.
Bucket Width (in Hz)
PSA Frequency Span (Hz)
PSA number of Sweep Points
1
–
--------------------------------------------------------------------------------
=
Bucket Width (in Hz)
150,000,000
601
1
–
------------------------------
250,000 Hz
=
=
PSA Start Frequency
Sweep Offset
Bucket Width
–
+
Harmonic Number
---------------------------------------------------------------------------------------------------------------------------------
2,850,000,000
1 000 000 000
,
,
,
250 000
,
–
+
2
----------------------------------------------------------------------------------------------------------
=
1,425,000,000
=
500,000,000
125,000 1 924,875,000
Hz 1.924875
GHz
=
,
=
–
+
PSA Stop Frequency
Sweep Offset
Bucket Width
+
+
Harmonic Number
---------------------------------------------------------------------------------------------------------------------------------
3 000,000,000
,
1,000,000,000
250,000
–
+
2
------------------------------------------------------------------------------------------------------
=
1,500,000,000
=
500,000,000
125,000 2 000,125,000
Hz 2.000125
GHz
=
,
=
+
+