2.
2.
0.785398163
tan
-1
0.6104
=
31.39989118
31°23’59”6
9-4) Hyperbolic functions and inverse hyperbolic
functions
sinh 3.6=
18.28545536
tanh 2.5=
0.986614298
cosh 1.5 - sinh 1.5 =
2.352409615
0.22313016
-1.5
sinh
-1
30 =
4.094622224
Solve tanh 4x = 0.88
0.343941914
sec (
π
rad ) =
1
3
cosec 30° =
1
=
sin 30°
cos (
π
rad )
3
cos
-1
2 =
2
x = tanh
-1
0.88 =
4
cos
-1
tan
-1
- 29 -
- 30 -
INV
INV HYP
RM
In
•
DMS
INV
cos
“RAD”
“DEG”
3
π
÷
=
=
1/x
INV
INV
INV
INV
X
•
M
“RAD” 2
6104
2
÷
•
sin
-1
tan
-1
HYP
HYP
HYP
HYP
HYP
sin
tan
cos
sin
3 •
2
1
30
88
6
5
5
4
•
•
•
÷
=
–
=
sin
“DEG” 30
1/x
M
M
M
M
RAD
• For the DMS display format, the integer part of the
display data is regarded as degree, 2 digits below the
decimal point as minute, and 3
rd
digits and below as
second. Therefore 14°25'36" = 14.2536
9-2) Angular conversion of data
45°= 0.785398163 rad = 50 grad
0.785398163.
50.
45.
9-3) Trigonometric / Inverse trigonometric functions
0.5
cos 63°52’41”=
63.87805556
0.440283084
tan (- 35 gra) =
-0.612800788
2 • sin45°xcos65°=
0.597672477
1.732050808
14 . 25 36
Degree Minute Second
sin (
π
rad ) =
6
cot 30° =
1
=
tan 30°
INV
sin
6
“RAD”
π
÷
=
cos
tan
5241
“DEG” 63 •
•
DEG
DRG
“GRAD” 35 +/-
sin
cos
“DEG” 2
65
45
x
x
=
tan
“DEG” 30
1/x
RAD
INV
45
RAD
GRAD
DEG
DEG
GRAD
DRG
INV
DRG
INV