Vandersteen Audio TREO Скачать руководство пользователя страница 5

 5 

 

216 divided by 3 is 72 (all to the nearest inch) 

 

216 divided by 5 is 43 

 

216 divided by 7 is 31 

 

216 divided by 9 is 24 

 

216 divided by 11 is 20 

 

216 divided by 13 is 17 (and so on; eventually  

the lines pile on top of each other or the speaker runs into 
the wall.)  The results are the distances in inches that the 
center of the speakers can be placed into the length of the 
room, away from the wall behind them, to minimize the 
nodes and anti-nodes. 
     Now we can graph these odd dimensions  distances on a 
drawing of the room.  We only need to graph them for the 
wall where we intend to place the speakers. 

S

ETTING-

U

T

HE 

S

PEAKERS 

The Model Treo requires a break-in period of at least 100 hours at a moderate 
volume level before its performance stabilizes.  Higher volume levels will not 
shorten this break in period. 

Vandersteen speakers will produce excellent, satisfying sound placed almost 
anywhere in a room.  With all the possible variables in room layout, there are 
no magical formulas for determining the best speaker placement in every room.  
Since every room is different, we recommend that you try the speakers in every 
domestically acceptable location to find where they sound the best in your par-
ticular listening environment.  The following sections contain suggestions that 
may be helpful in your placement experiments. 

S

PEAKER

 

P

LACEMENT 

O

DD 

D

IMENSIONS 

P

LACEMENT 

     Research on speaker placement has produced a method 
for reducing the nodes and anti-nodes in many rooms by 
positioning the loudspeakers on the odd dimensional inter-
sections of the room.  The odd dimensional intersections 
are the intersections of the imaginary lines you would 
draw if you divided the length of your room and the width 
of your room by odd numbers. 
     As an example, we will use a rectangular room measur-
ing 14 feet wide by 18 feet long.  We’ll assume that you 
want to set the speakers on one of the short walls, al-
though this method works equally well for long wall 
placement. 
     The first step is to take the length of the room, (18 feet 
in our example) convert it from feet to inches, (18 X 12 = 
216) and divide the result by odd numbers. 

17 

24 

31 

43 

72 

20 

     

We use the same method to figure how far the centers of 

the speakers should be from the side walls.  We take the 
width of the room, (14 feet) convert it from feet to inches,  

     Problems can arise when you attempt to place a given 
loudspeaker, either front radiating or dipole, into a typical 
domestic environment.  These problems are a function of 
the physical dimensions of the room.  The room’s dimen-
sions dictate where in the room a node or anti-node will 
occur.  Frequency response dips and peaks caused by 
nodes and anti-nodes can easily overwhelm the inherent 
accuracy of a loudspeaker. 
     If, for example, you place a loudspeaker with excellent 
frequency response characteristics in the corner of a room, 
you will increase response below about 200Hz by 6dB.  
This particular condition is a worst case example but simi-
lar conditions apply throughout the room to some extent. 

The Treo is not magnetically shielded and 
should be positioned at least 10 inches away 
from a direct view television set. 

Содержание TREO

Страница 1: ...ient response guarantees supe rior performance from records tapes CDs and video sources Custom en gineered drivers built exclusively for Vandersteen Audio are mounted in special baffles designed to ma...

Страница 2: ...tic situation dictates the use of a single ca ble per speaker you should use a multiple conductor single sheath cable to internally bi wire the speakers Some of these cables use different types of wir...

Страница 3: ...h frequency oscillation brightness and higher amplifier operating temperature We only recommend bi amplification when every com ponent in the system is the best available and there is no other path to...

Страница 4: ...teristics of the two wires in the middle frequencies to interfere with the proper blending of the woofer and midrange driver through the 600Hz crossover point The consistency of the sound will be seve...

Страница 5: ...n many rooms by positioning the loudspeakers on the odd dimensional inter sections of the room The odd dimensional intersections are the intersections of the imaginary lines you would draw if you divi...

Страница 6: ...nes will require that the listening position be offset to center it between the speakers Often the bass response of the system will be slightly more linear with the speakers placed on different width...

Страница 7: ...speaker would be placed exactly at the point where the two dimensions inter sect to realize the full benefits of odd dim ensions or third dimensions placement In a real room the actual best placement...

Страница 8: ...to the threaded holes on each front corner Be careful not to cross thread the cone it should go in easily By hand tighten the cone snug up against the bottom of the speaker Do not adjust right or left...

Страница 9: ...he current capability and therefore the dynamics and realism of the music A stable transistor amplifier will be able to deliver twice the wattage into 4 ohm load as is does into an 8 ohm load Amplifie...

Страница 10: ...and bass inputs sepa rately to determine which section of the speaker has the problem 3 Contact Vandersteen Audio Describe the problem and the steps you have taken to isolate the problem to the speake...

Страница 11: ...me with ferro fluid voice coil cooling Range of operation 5kHz to 30kHz Crossover 600Hz and 5kHz First order 6dB per octave Allows bi wiring with a single amplifier or vertical bi amplification with t...

Страница 12: ...ons and all the paperwork required to return the product after it is serviced The speaker must be packed in the original packing and returned to VANDERSTEEN AUDIO via insured freight by the customer a...

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