Siemens Sivacon S8, Планировочная информация

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SIVACON S8 Planning Principles – Reactive power compensation
Tab. 7/3: Configuration of capacitor modules
Cubicle
height Compensation
power per cubicle Number of
modules
Type
Non-choked Choked 5.67 %, 7 %, 14 %
1)
Without switch-
disconnector With switch-
disconnector Rear busbar
position Top busbar
position
Reactive power per cubicle: 600 kvar / 400 V / 50 Hz at 35 °C ambient temperature
2,200 mm 600 kvar 12 x 50 kvar + - - -
Cubicle power: up to 500 kvar / 400 V, 525 V, 690 V / 50 Hz at 35 °C ambient temperature
2,000 mm,
2,200 mm
50 kvar 2 x 25 kvar + + + +
100 kvar 4 x 25 kvar + + + +
150 kvar 6 x 25 kvar + + + +
200 kvar 4 x 50 kvar + + + +
250 kvar 5 x 50 kvar + + + +
300 kvar 6 x 50 kvar + + + +
350 kvar 7 x 50 kvar + - + +
400 kvar 8 x 50 kvar + - + +
2)
2,200 mm
400 kvar 8 x 50 kvar + + + +
2)
450 kvar 9 x 50 kvar + - + 2) -
500 kvar 10 x 50 kvar + - +
2)
-
1)
14 % choked only possible for 400 V
2)
Can only be implemented with degree of protection IP30 / IP31
Legend:
+ possible
- not possible
7.1 Configuration and calculation
When cubicles with direct connection to the main busbar
are configured, the selection of capacitor modules depends on the total power in this cubicle and the number of mod-
ules, as it becomes apparent in Tab. 7/3.
When calculating the required compensation power, you
can proceed as follows:
1. The electricity bill of the power supplier shows the
consumption of active energy in kWh and reactive energy
in kvarh. The distribution system operator (DSO) usually
requires a cos φ between 0.90 and 0.95. To avoid costs, the
value should be compensated to a cos φ near 1. Where
tan φ = reactive energy / active energy
2. From Tab. 7/4 the conversion factor F must be deter-
mined by compensation in dependency of the original
value for tan φ
1
(row) and the desired cos φ
2
(column).
3. The compensation power required is the product of the
conversion factor F and the mean active power consump-
tion P
m
Compensation power P
comp
= F x P
m
Example:
Reactive energy W
b
= 61.600 kvarh per month
Active energy W
w
= 54.000 kWh per month
tan φ
1
= W
b
/ W
w
= 1.14 (cos φ
1
= 0.66)
Mean power consumption P
m
P
m
= active energy / working time
= 54,000 kWh / 720 h
= 75 kW
Desired power factor cos φ
2
= 0.95
Conversion factor F (tan φ
1
= 1.14; cos φ
2
= 0.95)
F = 0.81
Compensation power P
comp
= F x P
m
= 0.81 x 75 kW
P
comp
= 60 kvar