Philips TDA6107JF, Техническое описание, Страница: 6 / 20

2002 Oct 18 6
Philips Semiconductors Product specification
Triple video output amplifier TDA6107JF
CHARACTERISTICS
Operating range: T
j
=
−
20 to +150
°
C; V
DD
= 180 to 210 V. Test conditions: T
amb
= 25
°
C; V
DD
= 200 V;
V
o(c1)
= V
o(c2)
= V
o(c3)
=
1
⁄
2
V
DD
; C
L
= 10 pF (C
L
consists of parasitic and cathode capacitance); R
th(h-a)
= 18 K/W
(measured in test circuit of Fig.8); unless otherwise specified.
SYMBOL PARAMETER CONDITIONS MIN. TYP. MAX. UNIT
I
q
quiescent supply current 5.6 6.6 7.6 mA
V
ref(int)
internal reference voltage
(input stage)
−
2.5
−
V
R
i
input resistance
−
3.6
−
k
Ω
G gain of amplifier 47.5 51.0 55.0
∆
G gain difference
−
2.5 0 +2.5
V
O(oc)
nominal output voltage at
pins 7, 8 and 9 (DC value) I
i
= 0
µ
A 116 129 142 V
∆
V
O(oc)(offset)
differential nominal output
offset voltage between
pins 7 and 8, 8 and 9 and
9 and 7 (DC value) I
i
= 0
µ
A
−
0 5 V
∆
V
o(c)(T)
output voltage temperature
drift at pins 7, 8 and 9
−
10
−
mV/K
∆
V
o(c)(T)(offset)
differential output offset
voltage temperature drift
between pins 7 and 8,
8 and 9 and 7 and 9
−
0
−
mV/K
I
o(m)(offset)
offset current of measurement
output (for three channels) I
o(c)
= 0
µ
A;
1.5 V < V
i
< 5.5 V;
1.8 V < V
o(m)
< 6 V
−
50
−
+50
µ
A
∆
I
o(m)
/
∆
I
o(c)
linearity of current transfer
(for three channels)
−
100
µ
A < I
o(c)
< 100
µ
A;
1.5 V < V
i
< 5.5 V;
1.8 V < V
o(m)
< 6 V
−
0.9
−
1.0
−
1.1
−
100
µ
A
≤
I
o(c)
< 10 mA;
1.5 V < V
i
< 5.5 V;
1.8 V < V
o(m)
< 4 V
−
0.9
−
1.0
−
1.1
I
o(c)(max)
maximum peak output current
(pins 7, 8 and 9) 50 V < V
o(c)
< V
DD
−
50 V
−
20
−
mA
V
o(c)(min)
minimum output voltage
(pins 7, 8 and 9) V
i
= 7.0 V; at I
o(c)
= 0 mA;
note 1
− −
10 V
V
o(c)(max)
maximum output voltage
(pins 7, 8 and 9) V
i
= 1.0 V; at I
o(c)
= 0 mA;
note 1
V
DD
−
15
− −
V
B
S
small signal bandwidth
(pins 7, 8 and 9) V
o(c)
= 60 V (p-p)
−
5.5
−
MHz
B
L
large signal bandwidth
(pins 7, 8 and 9) V
o(c)
= 100 V (p-p)
−
4.5
−
MHz
t
Pco
cathode output propagation
time 50% input to 50% output
(pins 7, 8 and 9) V
o(c)
= 100 V (p-p) square
wave; f <1 MHz;
t
r
= t
f
= 40 ns
(pins 1, 2 and 3);
see Figs 6 and 7
−
60
−
ns