20VS5-213
P. 3 / 4
EM-4429 Rev.1
APPLICATION EXAMPLES
The primary amplifier in this unit is high accurate. Installing external resistors to the inverting input (pin 2) and the feed-
back (pin 1), this unit can be used as a non-inverting or inverting amplifier.
The series resistance of the amplifier, R
1
+ R
2
must be 10 kΩ or more and 200 kΩ or less.
The output is proportional to the input.
The gain is 0.97.
E.g. ±9.7V DC for ±10V DC input.
The output is inverted to the input. The
gain is -1.
E.g. +10V DC for -10V DC input and -10V
DC for +10V DC input.
For a non-inverting amplification the out-
put is following.
V
O
= (1 + R
1
/ R
2
)
×
V
IN
When R
1
= 10kΩ, R
2
= 10kΩ, then the out-
put is following. The gain is 2.
V
O
= 2
×
V
IN
For an inverting amplification the output
is following.
V
O
= -(R
1
/ R
2
)
×
V
IN
When R
1
= 20kΩ, R
2
= 10kΩ, then the out-
put is following. The gain is -2.
V
O
= -(20kΩ / 10kΩ)
×
V
IN
= -2
×
V
IN
+
–
+
–
+
–
1
2
Non-inverting circuit G = 0.97
OUTPUT ±9.7V DC
–
+
REFERENCE
VOLTAGE SOURCE
n
Non-inverting amplifier circuit: Basic example of G = 0.97
INPUT ±10V DC
+
–
4
3
5
6
17
16
+
–
EXTERNAL CLOCK / POWER 0 - 15V
14
15
+
–
+
R
2
R
1
–
+
–
Inverting circuit G = -1
OUTPUT ±10V DC
■
Inverting amplifier circuit: Basic example of G = -1 (output inverted to the input) (R
1
≈
R
2
)
INPUT ±10V DC
+
–
–
+
REFERENCE
VOLTAGE SOURCE
1
2
4
3
5
6
17
16
+
–
EXTERNAL CLOCK / POWER 0 - 15V
14
15
+
–
+
R
2
R
1
–
+
–
Non-inverting amplifier circuit G = 1 + R
1
/ R
2
OUTPUT V
O
■
Non-inverting amplifier circuit: Example of G = 1 + R
1
/ R
2
INPUT V
IN
+
–
–
+
REFERENCE VOLTAGE SOURCE
1
2
4
3
5
6
+
–
EXTERNAL CLOCK / POWER 0 - 15V
17
16
14
15
+
–
+
R
2
R
1
–
+
–
Inverting amplifier circuit G = -R
1
/ R
2
OUTPUT V
O
■
Inverting amplifier circuit: Example of G = -R
1
/ R
2
(output inverted to the input)
INPUT V
IN
+
–
–
+
REFERENCE VOLTAGE SOURCE
1
2
4
3
5
6
+
–
EXTERNAL CLOCK / POWER 0 - 15V
17
16
14
15
