6
CORRECTION FACTORS
The given values have been calculated for
a high-speed fan. For a different speed,
the given values must be multiplied by the
following correction factors:
T
otal cooling cap
acity W
Sensible cooling cap
acity W
Room air temperature
with DB ºC
Room air temperature
with WB ºC
Low
speed
Medium
speed
Cooling
Capacity
W
ater inlet
temperature ºC
T
water ºC
COOLING CAPACITIES
3
4
9
8
7
6
5
10
4
9
8
7
6
5
10
11
12
13
3000
22
21
20
19
18
17
16
15
14
22
21
20
19
18
25
24
23
28
27
26
30
29
4000
5000
6000
7000
8000
9000
4000
5000
6000
7000
8000
9000
10000
11000
12000
070-2P
070-4P
090-4P
090-2P
070-4P
070-2P
090-4P
090-2P
EXAMPLE: For the unit CWC 090-2P with chilled water rise of T = 5
ºC, chilled water temperature 7 ºC and entering air temperature 27
ºC DB/19 ºC WB, according to the diagram the cooling capacity is:
Total cooling capacity = 8450 W
Sensible cooling capacity= 6600 W
To estimate the water flow use the formula Qw=Pt x 0.86
Qw = Water flow (l/h) T
Pt = Total cooling capacity (W)
T = Inlet water temperature - outlet water temperature (ºC)
For the example given Qw =1453 l/h and water pressure drop in page
8 is 28 Kpa.
DB : Dry bulb
WB : Wet bulb
0,8
0,9
COOLING CAPACITIES
3
4
9
8
7
6
5
10
4
9
8
7
6
5
10
11
12
13
3000
22
21
20
19
18
17
16
15
14
22
21
20
19
18
25
24
23
28
27
26
30
29
4000
5000
6000
7000
8000
9000
4000
5000
6000
7000
8000
9000
10000
11000
12000
070-2P
070-4P
090-4P
090-2P
070-4P
070-2P
090-4P
090-2P
EXAMPLE: For the unit CWC 090-2P with chilled water rise of T = 5
ºC, chilled water temperature 7 ºC and entering air temperature 27
ºC DB/19 ºC WB, according to the diagram the cooling capacity is:
Total cooling capacity = 8450 W
Sensible cooling capacity= 6600 W
To estimate the water flow use the formula Qw=Pt x 0.86
Qw = Water flow (l/h) T
Pt = Total cooling capacity (W)
T = Inlet water temperature - outlet water temperature (ºC)
For the example given Qw =1453 l/h and water pressure drop in page
8 is 28 Kpa.
DB : Dry bulb
WB : Wet bulb