JALpower JP9960, Руководство пользователя

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15
Model AC input breaker Bypass input
breaker
Battery switch N wire switch AC input
fuse
Battery input
fuse
JP9960 20K 3
φ
50A/380VAC
3
φ
63A/380VAC
3
φ
125A/380VAC
1
φ
80A/220VAC
63A
690V
30A 600V
JP9960 30K 3 φ
63A/380VAC
3 φ
80A/380VAC
3 φ
150A/380VAC
1 φ
100A/220VAC
80A
690V
30A 600V
JP9960 40K
3 φ
80A/380VAC
3 φ
100A/380VAC
3 φ
200A/380VAC
1 φ
150A/220VAC
100A
690V
30A
600V*2
JP9960 60K 3
φ
150A/380VAC
3
φ
150A/380VAC
3
φ
300A/380VAC
1
φ
200A/220VAC
100A
690V*2
100A
690V
JP9960 80K
3 φ
175A/380VAC
3 φ
175A/380VAC
3 φ
400A/380VAC
1 φ
250A/220VAC
100A
690V*2
100A
690V
Remark:
1. Prior to connecting the power distribution system to the UPS, make sure the
rated triploid-pole over-current breaker is installed to break off all the input lines
and the N line breaker can be configured individually.
2. When single-phase current exceeds 100A, switches of protective atmosphere
should be equipped with arc control devices,It should be D-curve air switch with
UL certification according to the customer requirement;
3. Battery positive/negative/N wire size: indicates UPS and battery bank wire size;
red wire signifies the positive polarity and black wire the negative, while blue wire
the neutral.
4. There should be the same length of the battery wires (positive, negative and N)
of being no more than 40m.
3.5 Parallel UPS installation
1. Redundancy introduction
N+X is currently the most reliable power supply structure, in which N indicates the
minimum UPS number required for the total load and X is the redundant UPS number,
namely, the malfunctioning UPS number that the system can simultaneously bear. The
larger X is, the higher reliability of system will be. For instance, if the total loads of a
customer register 55kVA, we can use JP9960 20K for N+X design. With N taking up 3,
X can be selected in accordance with reliability degree or cost requirement. Supposing
customer selects X=2 and equalized UPS power supply is 11 kVA for each unit, when
one set of UPS breaks down with malfunction, the remaining four sets will provide power
with almost 14kVA equalized current; if two sets of UPS fail, the remaining three sets of
UPS are supposed to provide power supply with almost 18kVA equalized current. The
maximum allowance of this system is for two sets of UPS going down at the same time,
the chances of which are much smaller than those of one UPS malfunction. Therefore,