GE Multilin G650, Руководство пользователя

Страница: 434 / 639

GEK-113285A G650 Generator Protection & Control System B-7
APPENDIX B B.3 DATA TYPE
B
B.3DATA TYPE
TYPE LENGTH DESCRIPTIÓN
F1 1 Boolean data type.
As it is a bit, for evaluating it we need a memory address and a bit. For example: Value
0x1A41-0001101001000001b
Bit 15 0
Bit 14 0
Bit 13 0
Bit 12 1
Bit 11 1
Bit 10 0
Bit 09 1
Bit 08 0
Bit 07 0
Bit 06 1
Bit 05 0
Bit 04 0
Bit 03 0
Bit 02 0
Bit 01 0
Bit 00 1
F2 2 Integer with 4 bytes sign.
It has to be scaled, by multiplying by 1000 the value to be sent, or dividing between 1000 the received value. For
example, if a value of 34509 is received, the converted value will be 34,509, and for writing value 334, we must send
334.000.
This prevents the loss of accuracy involved in using float values.
Example: 12312d=0x00003018.
Real Value = 12312/1000=12,312
F3 2 4-byte Floating
Example: 1240.5560x449B11CB
F4 1 Integer with 2 bytes sign.
Example: 1230x007B
F5 2 Integer without 4 bytes sign.
Example: 123120x00003018
F6 4 8 bytes Float
Example: 123.3240x405ED4BC6A7EF9DB
F7 1 Characters without sign. As it needs to be sent in a register, i.e. in two bytes, the character will go below.
Example: ‘
β
’x00E1
F8 1 Characters with sign As it needs to be sent in a register, i.e. in two bytes, the character will go below.
Example: ‘A’x0041
F9 16 String. Chain of characters with a fixed length (32 bytes). The end of the string is marked with a “\0”.
Example: “ABC”0x41x42x43x00....
F10 1 This is a 16-bit integer without sign. Each value that can be taken by this integer will have a correspondence in the
database Auxiliary Table. In this table we can find the corresponding chain, which must be shown for each value. In
the memory, only an integer value will be received.
Example: 0, 1Correspond to CLOSE, OPEN
F11 3 Milliseconds passed since 1/1/2000 at 00:00:00.000.