Procedure
1
m
STAT2
2 b
w
b
w
b
w
b
w
c
w
c
w
c
w
c
w
e
b
w
b
w
c
w
c
w
b
w
b
w
c
w
c
w
e
bbd
w
bbg
w
bdj
w
bdc
w
bdd
w
bd
b
w
bcg
w
bcc
w
3
3
(TEST)
f
(ANOVA)
4
2
(2)
c
1
(LIST)
b
w
c
1
(LIST)
c
w
c
1
(LIST)
d
w
c
1
(None)
c
5
1
(CALC)
6
(DRAW)
Result Screen
•
Time differential (A) :
Since P=0.2458019517 > 0.05 (level of significance), we can not reject the null hypothesis.
•
Temperature differential (B) :
Since P=0.04222398836 < 0.05 (level of significance), we can reject the null hypothesis.
•
Interaction (A
%
B) :
Since P=2.78169946e-3 < 0.05 (level of significance), we can reject the null hypothesis.
The above test indicates that the time differential is not significant, the temperature differen-
tial is significant, and interaction is highly significant.
25
examples
Содержание STAT 2
Страница 30: ...30 u u u u uInput Example u u u u uResults...
Страница 56: ...56 Calculation Result Output Example p F distribution probability...
Страница 64: ...Examples...