30
In this case 0.6 litres pesticide would have to be mixed
with 600 litres water to make up the spray solution.
However, in low-volume mistblowing only one quarter of
the water quantity is required for the same amount of
pesticide. This means that the concentration used is four
times higher than for high-pressure spraying. The 0.6
litres pesticide therefore have to be mixed with only 150
litres water. That is the quantity of solution required for
mistblowing 1 hectare. Finally, this quantity has to be
multiplied by the area to be treated in our example, i.e.
0.36 ha. The total quantity of solution to be applied to the
field is 54 litres.
Calculation
Area:
120 m • 30 m = 3,600 m
2
3,600 m
2
: 10,000 m
2
/ha = 0.36 ha
Solution/ha:
(acre):
0.6 l: 0.001 : 4 = 150 l
Required quan
tity of solution: 150 l/ha • 0.36 ha = 54 l
Note:
If the area to be treated is smaller than 1 hectare,
the quantity of solution required is less than the quantity
of solution per hectare (acre).
Note:
The increase in the strength of the mixture by a
factor of 4 was assumed for the purposes of this example.
Other mix ratios are possible in practical applications on
the basis of empirical values, special requirements or
explicit instructions.
The graph makes it easier to determine the quantity of
solution required. You can use a ruler and pencil to mark
in your own applications.
See enclosed graph 0457 352 0100