Siemens SIMATIC FM 453, Manual

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7-16
FM 453 Servo Drive / Step Drive Positioning Module
C79000-G7076-C453-01
END
Enter
MD59 = 0
MD57: Acceleration 1 a
b1
1. Calculate delay:
Acceleration element M
b1
determined (e.g. 2.4 Nm)
No Yes
a [Hz] =
10,000
@
M
b1
[Nm]
@
MD13
J
total
[kg
@
cm
2
]
@
2
@ π
(e. g. 272 837 Hz)
2. 20% certainty: a
b1
= 0.8
@
a (e.g. 218,269 Hz)
3. Enter rounded off value per MD 57 (e.g. 218,000 Hz/s)
MD59: Delay 1 a
v1
E.g. technological concerns may make a certain delay desirable, or friction torque
factors may provide a torque which deviates from the acceleration case. MD59 must
be either be calculated along the lines of the formula used to calculate MD57, or some
technologically desirable value must to be verified.
Should values for acceleration and delay be
identical within the range f < f
eg
?
MD58: Acceleration 2 a
b2
1. Acceleration torque M
b2
(e.g. 1.2 Nm)
2. Calculate delay:
a [Hz] =
10,000
@
M
b2
[Nm]
@
MD13
J
total
[kg
@
cm
2
]
@
2
@ π
(e.g. 136 418 Hz)
3. 20% certainty: a
b2
= 0.8 a (e.g. 109,134 Hz/sec)
4. Enter rounded off value per MD 58 (e.g. 109,000 Hz/sec)
J
total
= J
Motor
+ J
Load
J
total
= 7 kg
@
cm
2
MD60: Delay 2 a
v2
E.g. technological concerns may make a certain delay desirable, or friction torque
factors may provide a torque which deviates from the acceleration case. MD60 must
be either be calculated along the lines of the formula used to calculate MD58, or some
technologically desirable value must be verified.
Enter
MD60 = 0
Should values for acceleration and delay be
identical within the range f > f
eg
?
Yes
No
Equate acceleration element for all f --
f
max
: M
b1
= M
b2
Enter
MD55 = MD56
MD58 = 0
MD60 = 0
MD40: Frequency value for acceleration switchover f
eg
1. Enter M1 = 2 M2 - M
Load
into M diagram (e.g. 3 Nm)
2. Read f
eg
(e.g. 3,000 Hz) from frequency scale
3. Enter MD55 = f
eg
yes (e.g. 1.8 << 5)
No
Compare torque M2 with the idle time torque M0 of
the stepper motor: M2<< M0?
Parameterize the speed
profile by way of simple
ramp
Parameterize the speed
profile by way of bent
ramp
Read available motor torque M2 at f
max
(e.g. 1.8 Nm)
MD56: Maximum frequency f
max
1. Enter maximum frequency f
max
(e.g. 10,000 Hz) into the M diagram at maximum axis speed
2. Enter MD56 = f
max
MD54: Start/stop frequency f
ss
1. Enter J
Load
into J diagram (e.g. 3 kg cm
2
)
2. Determine f0 (e.g. 150 Hz) from intersection
with J curve
3. Shift base point of SS curve to f0
4. Enter M
Load
in M diagram (e.g. 0.6 Nm)
5. Determine f1 (e.g. 130 Hz) from intersection
with SS curve
6. Enter MD54 = f
ss
= 0.8 f1 (e.g. 104 Hz)
Fig. 7-6 Evaluation of Operating Characteristic Curves
Starting up the FM 453