
S t a t i c s S y s t e m
E x p . 8 : S l i d i n g F r i c t i o n
®
42
012-12876B
•
If the Friction Block stops, the mass is too light. If the Friction Block accelerates, the mass is too heavy.
•
The weight of the hanging mass that is sufficient to pull the Friction Block at a
constant speed
is
f
k
, the force
of the sliding (kinetic) friction between the Friction Block and the Inclined Plane.
Variables
Change the following factors and measure the sliding friction force.
•
Normal Force
: Add mass to the top of the Friction Block to increase the normal force between the block and
the Inclined Plane.
•
Contact Material
: Two sides of the Friction Block are bare wood. Two other sides are covered with felt.
Compare the sliding friction force for a wood surface to the sliding friction force for an equally sized felt sur-
face.
•
Contact Area
: The top and bottom surfaces have a larger area than the side surfaces. Compare the sliding
friction force for a larger area to the sliding friction force for a smaller area.
Reminders for each trial:
•
Carefully adjust the mass on the mass hanger until the weight of the hanging mass is enough so that the Fric-
tion Block moves at a very slow, constant speed after you give it a small push.
•
Record the total mass of the Friction Block, M, and the hanging mass, m, (total mass of the mass hanger and
added masses).
•
Calculate and record the normal force,
F
N
, of the Friction Block on the Inclined Plane and the sliding friction
force,
f
k
(
weight
of the hanging mass).
•
Calculate and record the coefficient of friction,
, which is the ratio of the sliding friction force,
f
k
, divided by
the normal force,
F
N
Data Table
*For trials 7 through 10, let the total mass of the Friction Block be constant.
Trial
Added Mass
(kg)
Total Mass,
M, of Block
Normal Force,
F
N
= Mg
Hanging
Mass, m
Friction
force, f
k
= mg
Coefficient of
friction,
= f
k
/F
N
1
0.000
2
0.050
3
0.100
4
0.150
5
0.200
6
0.250
Trial
Surface
Total Mass,
M, of Block*
Normal Force,
F
N
= Mg
Hanging
Mass, m
Friction
force, f
k
= mg
Coefficient of
friction,
k
= f
k
/F
N
7
Wood, Large
8
Felt, Large
9
Wood, Small
10
Felt, Small
Summary of Contents for ME-9502
Page 1: ... PASCO Mechanics Statics System ME 9502 Instruction Manual 012 12876B 012 12876 ...
Page 4: ... Statics System iv 012 12876B ...
Page 20: ...Statics System Exp 2 Adding Forces Resultants and Equilibriants 16 012 12876B ...
Page 24: ...Statics System Exp 3 Resolving Forces Components 20 012 12876B ...
Page 28: ...Statics System Exp 4 Torque Parallel Forces 24 012 12876B ...
Page 32: ...Statics System Exp 5A Center of Mass 28 012 12876B ...
Page 36: ...Statics System Exp 5B Equilibrium of Physical Bodies 32 012 12876B ...
Page 44: ...Statics System Exp 7 The Inclined Plane 40 012 12876B ...
Page 50: ...Statics System Static Friction on an Inclined Plane 46 012 12876B ...
Page 60: ...Statics System Exp 10 Simple Harmonic Motion The Simple Pendulum 56 012 12876B ...
Page 66: ...Statics System Exp 11A Simple Harmonic Motion Physical Pendulum 62 012 12876B ...
Page 70: ...Statics System Exp 11B Minimum Period of a Physical Pendulum 66 012 12876B ...
Page 76: ...Statics System Exp 11C Simple Harmonic Motion Beam on a Spring 72 012 12876B ...
Page 84: ...Statics System Exp 13 Simple Machines The Inclined Plane 80 012 12876B ...
Page 94: ...Statics System Technical Support 90 012 12876B ...