to object in mm
ls
D: Number of vertical pixels
0
: Number of vertical pixels = 400
bject = 300 mm
alculated focal length = (300 : (1 + (100 : 10,1))) = 27,5 mm
t size
mm, the distance from lens to object has to be
hanged as follows:
or size of
ns to object is calculated as:
nce from lens to object has to be reduced from 300mm to
61mm
focus of the lens will come to its limit. and the required magnification factor
]
[
1
]
[
mm
Size
Sensor
B
A
mm
Length
Focal
+
=
A: Distance from lens
B: Object size in mm
C: Number of horizontal pixe
1
,
10
400
600
014
,
0
]
mm
[
Size
2
2
=
+
⋅
=
Sensor
Example:
C: Number of horizontal pixels = 60
D
A: Distance from lens to o
B: Object size = 100 mm
c
when a lens with focal length of 24 mm has to be used, and the objec
has to be kept at 100
c
⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
+
⋅
=
Size
Sensor
Size
Object
Length
Focal
mm
Object
to
Distance
1
]
[
at a focal length of 24mm, an object size of 100mm and a sens
10,1mm the new distance from le
24
⋅
(1 + (100 : 10,1)) = 261 mm
The dista
2
Vice versa, when the distance from lens to object has to be reduced, the
CR Series
Ref. 1830-SU-02-G
Page 41
