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Model 2241-3 & 3i
Technical Manual
Section 8
Ludlum Measurements, Inc.
Page 8-16
January 2016
As an example, assume a 60-second count sample in a low field of 8
mR/hr:
Example
C/s
440
=
60
26,427
=
CORR
lo
Place detector in the high field and enter the counts per second:
Equation 8
s
counts
=
time
count
SAMPL
=
CORR
hi
hi
Counts/second sample in high field of 200 mR/hr:
Example
C/s
5830
=
1
5830
=
CORR
hi
Insert the values calculated in equations (5), (6), (7), and (8) and solve for f
d
:
Equation 9
s
units
=
CORR
CAL
x
CORR
-
CAL
=
f
lo
lo
hi
hi
d
Example
s
R
10
x
26.2
=
440
10
x
2.22
x
5830
-
10
x
55.6
=
f
d
6
6
6
Solve for a
d
:
Equation 10
s
count
units
=
)
CORR
x
CAL
(
-
)
CORR
x
CAL
(
=
a
2
hi
lo
hi
hi
d
Example
2
2
6
6
s
RCount
10
x
31.1
=
5830)
x
10
x
(2.22
-
5830)
x
10
x
(55.6
=
a
d
Summary of Contents for 2241-3
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