11
K R A M E R
E lectron ics
MATRIX ROUTING SWITCHER
NOTES on the above table:
NOTE 1
- These are bi-directional definitions. That is, if the switcher receives the code, it will perform
the instruction; and if the instruction is performed (due to a keystroke operation on the front panel),
then these codes are sent. For example, if the HEX code
01h
85h
88h
83h
was sent from the PC, then the switcher (Layer 3 = YUV) will switch input 5 to output 8. If the user
switched input 1 to output 7 via the front panel keypad, then the switcher will send:
41h 81h 87h 83h
to the PC.
When the PC sends one of the commands in this group to the switcher, then, if the instruction is valid,
the switcher replies by sending to the PC the same four bytes that it was sent (except for the first byte,
where the DESTINATION bit is set high).
NOTE 2
- The reply to a "REQUEST" instruction is as follows: the same instruction and INPUT codes
as were sent are returned, and the OUTPUT is assigned the value of the requested parameter. The
replies to instructions 10 and 11 are as per the definitions in instructions 7 and 8 respectively. For
example, if the present status of machine layer 5 (RGBhv) is breakaway setting, then the reply to the
HEX code
0Bh 80h 80h 85h
would be
4Bh 80h 81h 85h
NOTE 3
- An error code is returned to the PC if an invalid instruction code was sent to the switcher, or
if a parameter associated with the instruction is out of range (e.g. trying to switch a 16x16 matrix with
an input or output greater than 16, or trying to switch an input or output greater than the highest one
defined). This code is also returned to the PC if an RS-232 instruction is sent while the machine is
being programmed via the front panel. Reception of this code by the switcher is not valid.
NOTE 4
– The output VCAs are 32 logarithmic steps. Values are 0 to 31 (decimal).
NOTE 5
– The input levels are 32 logarithmic steps. Values are 0 to 31 (decimal) and coded in the 5
lowest bits of the output byte.
When bit 5 = 0, the gain value is taken.
When bit 5 = 1, the Balanced/Unbalanced mode is taken : bit 6 = 0 for Balanced mode, bit 6 = 1 for
Unbalanced mode.
The reply always contains the Balanced/Unbalanced mode and the Gain value under the binar form :
1 bal/unbal
1 G4 G3 G2 G1
G0
Where bal=0 and unbal=1
the reply to the HEX code
16h 82h 85h 81h
would be (for a balanced mode)
56h 82h A1h 81h
NOTE 6
– The Output VCAs are 32 logarithmic steps. Values (0 to 31 decimal) are replied in the
output byte.
The input levels are 32 logarithmic steps. Values are 0 to 31 (decimal) and coded in the 5 lowest bits
of the output byte.
The reply always contains the Balanced/Unbalanced mode and the gain value under the binar form :
