Application notes
PS3031-2440-0000
32
Version: 1.0
Example:
A load is operated continuously with 480 W (= 50% of the nominal output load).
From time to time a peak power of 1440 W (= 150% of the nominal output load) is required for 1 second.
• The question is: How often can this pulse be delivered without overloading the power supply?
◦ Draw a vertical line at P
PEAK
= 150% and a horizontal line where the vertical line crosses the curve
P
0
= 50%. Read the maximum duty cycle from the duty cycle axis (= 0.37)
◦ Calculate the required pause length T
0
(base load):
◦ Result: Required pause length = 1.7 s
◦ Max. repetition rate = pulse + pause length = 2.7 s
T
0
= (T
PEAK
- (DutyCycle x T
PEAK
)) / DutyCycle = (1 s - (0.37 x 1 s)) / 0.37 =
1.7 s
Further examples of pulse load tolerance
P
PEAK
P
0
T
PEAK
T
0
1440 W
960 W
1 s
>25 s
1440 W
0 W
1 s
>1.3 s
1200 W
480 W
1 s
> 0.75 s
1440 W
480 W
0.1 s
>0.16 s
1440 W
480 W
1 s
>1.6 s
1440 W
480 W
3 s
>4.9 s
