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Timing, IRIG-B and Pulses
8.4.4
Connecting Unmodulated IRIG-B
To drive multiple loads from a single 1094B timing output, make sure they are wired in parallel.
Some call this “daisy-chaining”, however the idea is to drive all of these loads in parallel from the
single output. It is much simpler to connect loads to unmodulated IRIG-B than for modulated.
This is because all of the loads are driven at the same voltage and each draws current directly from
the transmission line.
To determine capacity for Unmodulated IRIG-B, follow these steps:
1. determine the impedance (or resistance) of each connected load
2. divide the drive voltage (5 V) by the resistance of each device
3. sum up all the load currents for the total current for one clock output
4. the total current should not exceed 250 mA.
Another method is to determine the lumped impedance of all of the connected IED’s in parallel.
Then, determine the overall current by dividing the drive voltage (5 V) by the computed lumped
impedance value. This current should not exceed 250 mA.
Techniques for Lightly Loaded Outputs
For lightly loaded outputs, you may want to consider intentionally loading down the output with
a resistor. This technique tends to calm any overshoot and ringing that would otherwise occur
without it. For example, placing a 50-Ohm resistor across the load would increase the output
current by 100 mA, however it would require a resistor that would handle that load. Consider
using at least a 1-Watt resistor in this example. Two possibilities exist: (1) placing a loading
resistor across the load itself, and (2) placing a source resistor in series, at the output of the clock.
A source (series) resistor would also tend to drop the available voltage to the device, so make sure
that the voltage is adequate with suggestion #2.
8.4.5
Connecting Modulated IRIG-B
The total load capacity for the modulated IRIG-B driver depends on the type and number of
loads. The main difference in computing the load capacity for modulated IRIG-B and unmodulated
IRIG-B is that modulated IRIG-B decoders tend to be sensitive to the peak-to-peak voltage. With
adding loads, the 1094B modulated driver produces more current, which is passes through the
internal source resister, dropping the available output voltage. The open circuit voltage (i.e. no
loads) is approximately 4.5 Vpp, so any connected loads will cause the available voltage to drop.
The available output voltage (Vpp) with a known current is calculated in 8.2.
(8.2)
V pp
= 4
.
5
V pp
−
I
(19
.
6
Ohms
)
Therefore, if you had 10 mA of load current (I load) the available voltage (Vpp) would be 4.304
Vpp. If the load current equals 100 mA, then the available voltage would be 2.54 Vpp. So, you
can see how the increasing load current (i.e number of loads) affects the available drive voltage at
the clock output. See also Table 8.1.