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5000 Watt AC Inverter by Wagan Tech

9

User’s Manual—Read before using this equipment 

10

For example; if a 20 AH battery is discharged at a 1 amp rate, is will take 20 hours to 

discharge that battery. The terms “charged” and “discharged” relate to actual battery 

voltage. This means that the output voltage of a nominal 12 volt battery starts at 13.2 volts 

(fully charged) then drops to 10.6 volts (discharged). If the load on the battery causes 

the battery to discharge faster than the 20 hour rate, the capacity (AH) of the battery is 

measurably reduced (derated). Derating is a major run time factor. The curve below can help 

to determine what the battery bank can deliver under load. The results are used to estimate 

how much additional battery capacity is needed to achieve the desired run time. 

The left vertical numbers of the curve represents percentage of the battery capacity at the 20 

hour rate. In this example, the user needs a one hour run time. If the example battery is 220 

AH (20 hour rate), and the load is 220 amps that is 100% (horizontal number) of the AH (20 

hour rate), starting at the 100% horizontal point and looking up to the curve the results are 

that only 56% of the battery capacity is available. This means that a higher battery capacity 

is required to get the desired run time: one hour. The curve also shows that a load of 200% 

of the 20 hour rate yields only 31% of the battery capacity. The installer must carefully plan 

the capacity of battery bank or the run time may be seriously affected. To the inexperienced 

installer, several trial battery capacities may be required to make sure a large enough 

battery capacity is available to achieve the desired run time.

The curve can be applied to any lead acid battery under load providing that it has an AH 

rating at the 20 hour rate.

Continuing with the previous example, the 150 amp load will need to run for 10 hours, so 

we begin configuration with a 1,500 AH battery. If the vertical is 1,500 and the horizontal 

is 150 amps, the percentage of load on the battery is 10%. The curve shows that the 1,500 

AH is derated to 90% of maximum. This means that the battery will have to be 16,500 AH 

for the full 10 hour run time. It is important to add some extra battery capacity, because as 

the batteries age they will lose AH capacity.

CONFIGURATING THE BATTERY BANK

Six volt, 220 AH “golf cart” batteries were selected for these illustrations because they are 

generally readily available and relatively inexpensive. They are deep-cycle type and with 

regular recharging they have a relatively long life. These batteries are “flooded” type; they 

freely vent hydrogen and oxygen while under charging and heavy discharge. They must be 

vented to outside air to prevent accumulation of explosive gases.

Fusing Requirements

NOTE:  It is important that for this 5000 watt inverter has two ANL 400 ampere or 

equivalent main battery fuses be added to the positive (+) battery cable as close as possible 

to the battery bank’s positive terminal. The fuse amperage rating must be sized to allow 

simultaneous operation of all the AC appliances to be powered, allowing for the momentary 

high startup current requirements of inductive loads. Use the recommended fuse block (fuse 

holder) and fuse, or an electrical equivalent. ANL type fuses and fuse holders are readily 

available from marine supply dealers.

The fuses are very important to protect equipment, batteries and personnel. The fuses protect 

against battery explosion if the cables that connect to the inverter accidentally short.  

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© 2010 Wagan Corporation

All Rights Reserved

Wagan and wagan.com are trademarks used by Wagan Corporation

Содержание AC Inverter

Страница 1: ...Item no 2012 User s Manual 5000 Watt AC Inverter R ...

Страница 2: ...ide LOAD CONSIDERATIONS When an appliance with a motor starts it requires an momentary surge of power This surge of power is the starting load or peak load Once started the appliance requires less power to continue to operate This is known as the continuous load It is important to know the starting loads and the continuous loads of the appliances that are to be powered by the inverter Appliance po...

Страница 3: ...ltage at the DC terminals of the inverter not actual battery voltage During high wattage applications the display may show a lower voltage level than the battery because of voltage drop that occurs between the DC input cables and the battery This voltage drop should not be greater than 0 25 volts as a greater voltage will seriously reduce run time This inverter will operate with input voltage rang...

Страница 4: ...nary AC voltmeters are calibrated to read average voltage and assume that the AC waveform will be a pure sine wave These meters will not correctly read MSW voltage and will display about 20 to 30 volts too low Any multi meter identified as TRUE RMS will accurately read MSW correctly INVERTER OUTPUT CHARACTERISTICS The high output terminals and outlets of this inverter are wired in a similar manner...

Страница 5: ...watts this can cause immediate overload shut down At 5 000 watts continuous output this inverter requires a DC power supply battery bank that can continuously supply 500 amps at 12V DC for the duration of the run time CONFIGURING THE BATTERY BANK To determine the minimum battery ampere hour rating that you will need to operate appliances from the inverter and any DC appliances powered by the batte...

Страница 6: ...id battery under load providing that it has an AH rating at the 20 hour rate Continuing with the previous example the 150 amp load will need to run for 10 hours so we begin configuration with a 1 500 AH battery If the vertical is 1 500 and the horizontal is 150 amps the percentage of load on the battery is 10 The curve shows that the 1 500 AH is derated to 90 of maximum This means that the battery...

Страница 7: ... front panel of the inverter is in the OFF 0 position Disconnect any remote switch from the connector on the front panel 4 Locate the ground lug terminal at the rear of the inverter Connect an insulated 6 gage copper wire to the terminal The other end of the ground wire is connected to a proper grounding point Use the shortest practical length of wire Connect this wire to the chassis of your vehic...

Страница 8: ... has 16 500 AH of capacity as in the example above and has been discharged to 10 5 volts discharged The charger has to replace 2145 AH 1650 x 1 3 AH in 14 hours So the charger must charge at a rate of 153 amps for 14 hours As this charge current is distributed among the batteries in the battery bank the current received by an individual battery is within its charge rating Be sure that the battery ...

Страница 9: ...or weak battery condition Recharge or replace battery Inadequate power being delivered to the inverter or excessive voltage drop Use lower gauge wire Keep wire length as short as possible PROBLEM TV does not work Reason Solution TV does not turn on Contact TV manufacture to see if the TV is compatible with a modified sine wave SPECIFICATIONS Name Description Input 12V 10 15V DC Output 115V AC Outp...

Страница 10: ...on will at its option replace or repair the defective part A Returned Merchandise Authorization number RMA is REQUIRED when sending in any defective item WAGAN Corporation is not responsible for any item s returned without an official Returned Merchandise Authorization number The item s must be returned with prepaid shipping WAGAN Corporation is not responsible for any shipping charges incurred in...

Страница 11: ...agan com U S A CAN Toll Free 1 800 231 5806 1 510 471 9221 31088 San Clemente Street Hayward CA 94544 U S A 2008 2010 Wagan Corporation All Rights Reserved Wagan and wagan com are trademarks used by Wagan Corporation Revised May 2010 ...

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