SPXFLOW Seital Separation SE 40CX-Q2P2, Инструкция по эксплуатации, Страница: 60 / 126

Chapter 8
SEITAL S.r.l. Rev. 1 of 14/01/97
Page 8-4 Use and maintenance handbook: Centrifugal separator
SE 40CX
The reduction of the solids content required to the machine is provided by:
Percentage of solids reduction = % solids in the inlet - % solids in the outlet = 7 - 2 = 5 %
The quantity of separated solids in one hour is worth:
Separated solids = Capacity x Percentage of solids reduction = 2.500 x 5/100 = 125 l/h
The useful volume of the solids chamber (which collects the separated solids) is calculated
by introducing a safety factor being equal to 0,8. If the total volume of the solids chamber
is V = 10 l, then:
Useful volume = Total volume x Coeff. of safety = 10 x 0,8 = 8 l
Now it must be calculated how many times the solids chamber is filled up in one hour:
n = Separated solids / admittable capacity = 125 / 8 = 15,625

16 times *
* always rounded up by excess.
The separation time (time between a discharge and the other) must be then:
Time of separ. = Second in one hour / N° fillings in one hour = 3600 / 16 = 225 sec.
ATTENTION
Danger of motor and coupling overheating.
The separation time must never be lower than 3 minutes.
b) For a product with a medium-low solids content (lower than 1 % apx) we recommend a
separation cycle with partial discharges (Prog n°1) or with partial discharges and total
discharges (Prog. n° 3). The separation time may be calculated in first approximation by
following the procedure indicated below, keeping into consideration the fact that with
partial discharges you only have a partial emptying of the bowl. For this reason a correct
setting of the discharge time (opening time of the bowl) which consider the volume of
solids actually discharged must be performed.
ATTENTION
The following instructions have an orientative meaning because the adjust of the working
cycle is extremely conditioned by the characteristics of the products and the physical
parameters of the process (capacity, temperature, viscosity, density, etc.).
Example
Process data Capacity 2.500 l/h
Content of solids in the inlet 0,5 %
Content of solids desired in the output 0 %
The reduction of the solids content required to the machine is 0,5 %:
The quantity of separated solids in one hour is:
Separated solids = Capacity x Percentage of solids reduction = 2.500 x 0,5/100 = 12,5 l/h