7
PROCESSING TIME
7.3 Cyclic Transmission Delay Time
7.3.2 Transmission delay time calculation example
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(b) Link scan time (
(c) Link refresh time (
Section 7.2 Link Refresh Time)
(d) Cyclic transmission delay time (
Section 7.3.1 Cyclic Transmission Delay
LS = [KB + (N × 56) + {LB + LY + (LW × 16)} 8 × 0.016
+ (N
T
× T × 30)] 1000 + Nc [ms]
(1) Sending-side link scan time, receiving-side link scan time
LS
T
, LS
R
= [1100 + (3 × 56) + {1024 + 0 + (1024 × 16)} 8 × 0.016
+ (0 × 2 × 30)] 1000
= 1.30 [ms]
(1) Sending-side link refresh time, receiving-side link refresh time
T, R = 0.09 + 0.41 × 10
-3
× {(1024 + 0 + 0 + 512) 16 + 1024 + 512} + 0 + 0
= 0.76 [ms]
(2) Link refresh time between relay station and sending side (for transfer)
MT = 0.09 + 0.41 × 10
-3
× {(1024 + 0 + 0 + 512) 16 + 1024 + 512} + 0 + 0.04
= 0.80 [ms]
L = (64 16 + 0) × 0.73 × 10
-3
+ 25 × 10
-3
+ (4 × 10
-3
× 2)
= 0.04 [ms]
(3) Link refresh time between relay station and receiving side (for transfer)
MR = 0.09 + 0.41 × 10
-3
× {(1024 + 0 + 0 + 512) 16 + 1024 + 512 } + 0 + 0.03
= 0.79 [ms]
L = (32 16 + 0) × 0.73 × 10
-3
+ 25 × 10
-3
+ (4 × 10
-3
× 1)
= 0.03 [ms]
Transmission delay time (for Universal model QCPU) =
(ST + T) + (LS
T
× 1) + MR + MT + (LS
R
× 1) + (SR × 2) + R [ms]
= (1 + 0.76) + (1.30 × 1) + 0.79 + 0.80 + (1.30 × 1) + (1 × 2) + 0.76
= 8.71 [ms]
[Data link transfer time for Universal model QCPU]
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