Application examples
Accelerating and decelerating with constant path
3−5
l
EDSVF9383V−EXT EN 2.0
3.3
Accelerating and decelerating with constant path
Use the basic configuration C0005 = 1000 with the changes shown in Fig. 3−2. However, set
C0104 = 2.
t
T
if
T
if
T
ir
T
ir
n
Fig. 3−3
Accelerating and decelerating with constant path (C0104 = 2)
n
Setpoint 1
Setpoint 2
Speed
T
ir
T
if
Acceleration time
Deceleration time
The distance is proportional to the number of motor revolutions. The distances are selected by
setting the Ti times (C0012, C0013).
l
The number of motor revolutions during acceleration or deceleration are calculated according
to the following formula:
N
+
n
max
60
@
T
i
2
N
Number of motor revolutions
n
max
Maximum speed (value in C0011)
T
i
Acceleration time T
ir
(value in C0012) or deceleration time T
if
(value in
C0013)
Содержание 9300 vector Series
Страница 8: ...Preface Definition of notes used 1 6 l EDSVF9383V EXT EN 2 0...
Страница 188: ...Application examples Centre winder with internal diameter calculation 3 18 l EDSVF9383V EXT EN 2 0...
Страница 192: ...Signal flow charts Speed control 4 4 l EDSVF9383V EXT EN 2 0 Fig 4 1 Basic configuration 1000 speed control sheet 1...
Страница 205: ...Signal flow charts Step control 4 17 l EDSVF9383V EXT EN 2 0 Fig 4 13 Basic configuration 2000 step control sheet 1...
Страница 211: ...Signal flow charts Torque control 4 23 l EDSVF9383V EXT EN 2 0 Fig 4 17 Basic configuration 4000 torque control sheet 1...