Required Opening = CFM / 300 FPM
Example:
Given:
Qty of 4 units in a mechanical yard, surrounded by a fence. Units are 2TWR3048A1 -
Required:
Determine free air opening space required in fence -
Solution:
4400 CFM X Qty of 4 = 17,600 CFM
17600 CFM / 300 FPM = 58.67 square feet
Round 58.67 to 59 square feet of free air opening in the 4 fence sections surrounding the mechanical yard.
*Table produced August 2006. For the most current information, please refer to specific equipment Product
Data.
Pg. 19
XR13 and XR14 Outdoor Unit Airflow Table
2TTR3 / 2TWR3
2TTR4 / 2TWR4
4TTR3 / 4TWR3
4TTR4 / 4TWR4
Unit Model Number
CFM
Unit Model Number
CFM
Unit Model Number
CFM
Unit Model Number
CFM
2TTR3018A1
1565
2TTR4018A1
2000
4TTR3018A1
3010
4TTR4018A1
2250
2TTR3024A1
2500
2TTR4024A1
2800
4TTR3024A1
3160
4TTR4024A1
2725
2TTR3030A1
3320
2TTR4030A1
3100
4TTR3030A1
3160
4TTR4030A1
2900
2TTR3036A1
4400
2TTR4036A1
3100
4TTR3036A1
3160
4TTR4036A1
3100
2TTR3042A1
4400
2TTR4042A1
4400
4TTR3042A1
4610
4TTR4042A1
4150
2TTR3048A1
4800
2TTR4048A1
4400
4TTR3048A1
4610
4TTR4048A1
4150
2TTR3060A1
4800
2TTR4060A1
4400
4TTR3060A1
4610
4TTR4060B1
4150
2TWR3018A1
1565
2TWR4018A1
2230
4TWR3018A1
3170
2TWR3024A1
2485
2TWR4024A1
2835
4TWR3024A1
3170
4TWR4024A1
2710
2TWR3030A1
2800
2TWR4030A1
3915
4TWR3030A1
3170
4TWR4030A1
3200
2TWR3036A1
4400
2TWR4036A1
4100
4TWR3036A1
4820
4TWR4036A1
4100
2TWR3042A1
4400
2TWR4042A1
4244
4TWR3042A1
4820
4TWR4042A1
4200
2TWR3048A1
4400
2TWR4048A1
4185
4TWR3048A1
4820
4TWR4048A1
4200
2TWR3060A1
4960
2TWR4060A1
4250
4TWR3060A1
4820
4TWR4060A1
4090